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Mashcka [7]
4 years ago
11

Simplify (2-1)+3^2÷3

Mathematics
2 answers:
sergeinik [125]4 years ago
8 0
I believe the answer to your question is 4
Solnce55 [7]4 years ago
7 0
(2 - 1) + 3^2 ÷ 3

= 1 + 9 ÷ 3

= 1 + 3

= 4
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Plz help it’s due tonight!!!
gogolik [260]

Answer:

x = 12

A = 83

B = 38

c = 59

Step-by-step explanation:

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Susan wants to hire one of two mechanics to repair her car. Each mechanic charges a one-time fee in
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there no table showing mechanic b. but mechanic a charges a one time fee of $50

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3 years ago
Estimate a 15% tip on a lunch bill of $78.42 by first rounding the bill amount to the nearest ten dollars.
Ludmilka [50]

Answer:

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3 years ago
Find the projection of u = <–6, –7> onto v = <1, 1> a. <-13/2,-13/2> b. <39,91/2> c. <-13/1764,-13/17
Alexandra [31]
<h2>Answer:</h2>

a. <-13/2,-13/2>

<h2>Step-by-step explanation:</h2>

The projection of a vector u onto another vector v is given by;

proj_vu = (\frac{u.v}{|v|^2})v               ----------------(i)

Where;

u.v is the dot product of vectors u and v

|v| is the magnitude of vector v

Given:

u = <-6, -7>

v = <1, 1>

These can be re-written in unit vector notation as;

u = -6i -7j

v = i + j

<em>Now;</em>

<em>Let's find the following</em>

(i) u . v

u . v = (-6i - 7j) . (i + j)

u . v = (-6i) (1i) + (-7j)(1j)          [Remember that, i.i = j.j = 1]

u . v = -6 -7 = -13

(ii) |v|

|v| = \sqrt{(1)^2 + (1)^2}

|v| = \sqrt{2}

<em>Substitute these values into equation (i) as follows;</em>

proj_vu = [\frac{-13}{(\sqrt{2}) ^2}][i + j]

proj_vu = \frac{-13}{2} [i + j]

This can be re-written as;

proj_vu = \frac{-13}{2}i + \frac{-13}{2}j

proj_vu =

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3 years ago
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baherus [9]
The answer is: C (I took the test)
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