Answer:
Percentile 5
And if we solve for a we got
Percentile 95
And if we solve for a we got
Step-by-step explanation:
Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:
Where 
and 
We want to find the percentiles 5 and 95 for this case.
Percentile 5
For this part we want to find a value a, such that we satisfy this condition:
(a)
(b)
We want to find a percentile with 0.95 of the area on the left and 0.05 of the area on the right it's z=-1.64. On this case P(Z<-1.64)=0.05 and P(z>-1.64)=0.05
Using this condition we got:
Replacing we got:
And if we solve for a we got
Percentile 95
And if we solve for a we got
Kindly find complete question attached below
Answer:
Kindly check explanation
Step-by-step explanation:
Given a normal distribution with ;
Mean = 36
Standard deviation = 4
According to the empirical rule :
68% of the distribution is within 1 standard deviation of the mean ;
That is ; mean ± 1(standard deviation)
68% of subjects :
36 ± 1(4) :
36 - 4 or 36 + 4
Between 32 and 40
2.)
95% of the distribution is within 2 standard deviations of the mean ;
That is ; mean ± 2(standard deviation)
95% of subjects :
36 ± 2(4) :
36 - 8 or 36 + 8
Between 28 and 44
3.)
99% is about 3 standard deviations of the mean :
That is ; mean ± 3(standard deviation)
99% of subjects :
36 ± 3(4) :
36 - 12 or 36 + 12
Between 24 and 48
What do u need help with ????
To convert to percent from fraction you divide the numerator by the denominator. from percent to decimal you move two decimal places to the left.
Answer:
8
Step-by-step explanation:
b=8
c=2
(8)(2)-(2)^3 = 16-8 =8
