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Evgen [1.6K]
3 years ago
6

What is the value of x/3y , when x = 18 and y = 3? 3/18 2 3 6

Mathematics
2 answers:
jek_recluse [69]3 years ago
5 0
Answer is 18/(3*3)=18/9=2
Anestetic [448]3 years ago
4 0

x = 18

y = 3

x/3y becomes 18/3(3) = 18/9 = 2

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A rope is 84 meters long is cut int two pieces so that one piece is 18 meters longer than the other. What is the length of each
Tpy6a [65]

Answer:

33 meters

51 meters

Step-by-step explanation:

84-18= 66

66/2= 33

33+18= 51

Check your answer:

51+33=84

5 0
3 years ago
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The princess examines one plant and can’t seem to locate its roots. The plant is labeled as p(x)=x^2+x+3 Which values should the
AleksAgata [21]
Let's actually find the roots, using the quadratic formula:

<span>p(x)=x^2+x+3 gives us a=1, b=1 and c=3.

                 -1 plus or minus sqrt(1^2-4(1)(3))
Then x = -----------------------------------------------          
                                           2

The discriminant here is negative, so the roots x will be complex:

              -1 plus or minus sqrt(-11)      -1 plus or minus i*sqrt(11)
       x = ---------------------------------- = -------------------------------------
                          2                                                 2

These are irrational roots; they cannot be expressed as the ratios of integers.</span>
8 0
4 years ago
Worth 80 points how much wood would a wood chuck chuck if a wood chuck could chuck wood!?!? I need to know a legit number and ho
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Answer:

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Step-by-step explanation:

7 0
3 years ago
A van is traveling 1.5 km per minute. How fast is the van traveling in miles per hour?
ipn [44]

Answer:

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Step-by-step explanation:

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3 0
3 years ago
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please show on graph (with x and y coordinates) state where the function x^4-36x^2 is non-negative, increasing, concave up​
babunello [35]

Answer:

y'' =12x^2 -72=0

And solving we got:

x=\pm \sqrt{\frac{72}{12}} =\pm \sqrt{6}

We can find the sings of the second derivate on the following intervals:

(-\infty Concave up

x=-\sqrt{6}, y =-180 inflection point

(-\sqrt{6} Concave down

x=\sqrt{6}, y=-180 inflection point

(\sqrt{6} Concave up

Step-by-step explanation:

For this case we have the following function:

y= x^4 -36x^2

We can find the first derivate and we got:

y' = 4x^3 -72x

In order to find the concavity we can find the second derivate and we got:

y'' = 12x^2 -72

We can set up this derivate equal to 0 and we got:

y'' =12x^2 -72=0

And solving we got:

x=\pm \sqrt{\frac{72}{12}} =\pm \sqrt{6}

We can find the sings of the second derivate on the following intervals:

(-\infty Concave up

x=-\sqrt{6}, y =-180 inflection point

(-\sqrt{6} Concave down

x=\sqrt{6}, y=-180 inflection point

(\sqrt{6} Concave up

8 0
3 years ago
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