Answer:
The probability is ![P(X >300 ) = 0.97219](https://tex.z-dn.net/?f=P%28X%20%20%3E300%20%29%20%3D%200.97219%20)
Step-by-step explanation:
From the question we are told that
The capacity of an Airliner is k = 300 passengers
The sample size n = 320 passengers
The probability the a randomly selected passenger shows up on to the airport
![p = 0.96](https://tex.z-dn.net/?f=p%20%3D%200.96)
Generally the mean is mathematically represented as
=>
=>
Generally the standard deviation is
![\sigma = \sqrt{n * p * (1 -p ) }](https://tex.z-dn.net/?f=%5Csigma%20%3D%20%20%5Csqrt%7Bn%20%2A%20%20p%20%2A%20%20%281%20-p%20%29%20%7D)
=> ![\sigma = \sqrt{320 * 0.96 * (1 -0.96 ) }](https://tex.z-dn.net/?f=%5Csigma%20%3D%20%20%5Csqrt%7B320%20%20%2A%20%200.96%20%2A%20%20%281%20-0.96%20%29%20%7D)
=> ![\sigma =3.50](https://tex.z-dn.net/?f=%5Csigma%20%3D3.50%20)
Applying Normal approximation of binomial distribution
Generally the probability that there will not be enough seats to accommodate all passengers is mathematically represented as
![P(X > k ) = P( \frac{ X -\mu }{\sigma } > \frac{k - \mu}{\sigma } )](https://tex.z-dn.net/?f=P%28X%20%20%3E%20k%20%29%20%3D%20%20P%28%20%5Cfrac%7B%20X%20-%5Cmu%20%7D%7B%5Csigma%20%7D%20%20%3E%20%20%5Cfrac%7Bk%20-%20%5Cmu%7D%7B%5Csigma%20%7D%20%29)
Here ![\frac{ X -\mu }{\sigma } =Z (The \ standardized \ value \ of \ X )](https://tex.z-dn.net/?f=%5Cfrac%7B%20X%20-%5Cmu%20%7D%7B%5Csigma%20%7D%20%20%3DZ%20%28The%20%5C%20standardized%20%5C%20%20value%20%5C%20%20of%20%20%5C%20X%20%29)
=>![P(X >300 ) = P(Z > \frac{300 - 307.2}{3.50} )](https://tex.z-dn.net/?f=P%28X%20%20%3E300%20%29%20%3D%20%20P%28Z%20%3E%20%20%5Cfrac%7B300%20-%20307.2%7D%7B3.50%7D%20%29)
Now applying continuity correction we have
=> ![P(X >300 ) = P(Z > \frac{[300.5] - 307.2}{3.50} )](https://tex.z-dn.net/?f=P%28X%20%20%3E300%20%29%20%3D%20%20P%28Z%20%3E%20%20%5Cfrac%7B%5B300.5%5D%20-%20307.2%7D%7B3.50%7D%20%29)
=> ![P(X >300 ) = P(Z > -1.914 )](https://tex.z-dn.net/?f=P%28X%20%20%3E300%20%29%20%3D%20%20P%28Z%20%3E%20%20-1.914%20%29)
From the z-table
![P(Z > -1.914 ) = 0.97219](https://tex.z-dn.net/?f=P%28Z%20%3E%20%20-1.914%20%29%20%3D%20%200.97219)
So
![P(X >300 ) = 0.97219](https://tex.z-dn.net/?f=P%28X%20%20%3E300%20%29%20%3D%200.97219%20)
The square root of 9 is 3
Answer:
Graphing
Step-by-step explanation:
1) You can graph this equation by using y=mx+b. You can replace that equation with y=3x-1.
M=3
X=x
B=-1
On a graph you would down 1 since it's negative and make a point. Then you would put a 1 under the 3 to make it a fraction. 3/1. Then you would divide 1 by 3 (1 ÷ 3). Then you would go to the right 0.33 because it's positive, and the up 1. Then you would make a second point.
This would only give you one line which wouldn't give you an intersection.