can u add the table so its easier
Answer:
Since the sum is same, the associative property of addition holds true. Therefore, it can be concluded that the grouping of numbers in any order does not change the sum. Example 6: Consider the algebraic expression, .
Step-by-step explanation:
not sure
I see right away that 3 can be factored out of <span>15xy − 45x − 6y + 18.
The quotient is 5xy - 15x - 2y + 6, so that
</span>15xy − 45x − 6y + 18 = 3(5xy − 15x − 2y + 6) (2 factors)
<span>
or 3 [ 5x(y-1] - 2 [y-3])
</span>
<u>the correct question is</u>
The denarius was a unit of currency in ancient rome. Suppose it costs the roman government 10 denarii per day to support 4 legionaries and 4 archers. It only costs 5 denarii per day to support 2 legionaries and 2 archers. Use a system of linear equations in two variables. Can we solve for a unique cost for each soldier?
Let
x-------> the cost to support a legionary per day
y-------> the cost to support an archer per day
we know that
4x+4y=10 ---------> equation 1
2x+2y=5 ---------> equation 2
If you multiply equation 1 by 2
2*(2x+2y)=2*5-----------> 4x+4y=10
so
equation 1 and equation 2 are the same
The system has infinite solutions-------> Is a consistent dependent system
therefore
<u>the answer is</u>
We cannot solve for a unique cost for each soldier, because there are infinite solutions.
