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3 years ago

Find the slope and y-intercept of the following graph.

Mathematics

1 answer:

Orlov [11]3 years ago

6 0

Answer: y = -5*x + b

Step-by-step explanation:

A line is written as:

y = a*x + b

where a is the slope and b is the y-intercept.

IIf we have a line that passes through the points (x1, y1) and (x2, y2) then the slope of the line is:

a = (y2 - y1)/(x2 - x1)

In this case we can see that the line passes through the points:

(0, 2) and (1, - 3)

Then the slope is:

a = (-3 - 2)/(1 - 0) = -5

Then our line is:

y = -5*x + b

And when x = 0, y = 2 then:

y = 2 = -5*0 + b

2 = b

Our line is:

y = -5*x + b

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A triangle has side lengths of (8d – 3) centimeters, (6d + 2) centimeters, and

alisha [4.7K]

The perimeter of a triangle is the sum of its side lengths.

The perimeter of the triangle is: $14d + 7f +7$

<u>The sides of the triangle are:</u>

Side 1 = (8d - 3) cm

Side 2 = (6d + 2) cm

Side 3 = (7f + 8) cm

The perimeter (P) is calculated as:

P = Side 1 + Side 2 + Side 3

So, we have:

$P = (8d - 3) + (6d + 2) + (7f + 8)$

Remove brackets

$P = 8d - 3 + 6d + 2 + 7f + 8$

Collect like terms

$P = 8d + 6d + 7f - 3 + 2 + 8$

$P = 14d + 7f +7$

Hence, the perimeter of the triangle is: $14d + 7f +7$

Read more about perimeters at:

brainly.com/question/6465134

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3 years ago

you increase your walking speed from 1 m/s to 3 m/s in a period of 1 s. What is your acceleration? A) 2 m/s ^2 B) 3 m/s ^2 C) 5

arsen [322]

Acceleration is to change in speed divided by the time for the change. Change in speed is end speed minus started speed.

3m/s-1m/s and equals to 2m/s.

The answer should be A. (2m/s^2.)

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Have a great day!

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3 years ago

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Montano1993 [528]

Answer:

multiplication property of equality

Step-by-step explanation:

Since we are multiplying by the same amount on each side, we are using the multiplication property of equality

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3 years ago

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KATRIN_1 [288]

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3 years ago

Find the exact length of the curve. x = 9 + 9t2, y = 6 + 6t3, 0 ≤ t ≤ 4

andrew11 [14]

ANSWER

$=102 \sqrt{ 17}$

EXPLANATION

The equation of the curve is:

$x = 9 + 9 {t}^{2}$

$y = 6 + 6 {t}^{3}$

We differentiate to obtain:

$\frac{dx}{dt} = 18t$

$\frac{dy}{dt} = 18t$

The length of the arc

$l = \int _0 ^{4} \sqrt{ {( \frac{dx}{dt} )}^{2} + {( \frac{dy}{dt} )}^{2} } dt$

This implies that:

$= \int _0 ^{4} \sqrt{ {( 18t )}^{2} + {( {18 {t}^{2} } )}^{2} } dt$

$= \int _0 ^{4} 18t \sqrt{ 1+ { {18 {t}^{2} } }} dt$

$=102 \sqrt{ 17}$

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3 years ago