Answer:
$13
Step-by-step explanation:
Let's set up a ratio...
2:3.25
8:x
We know 2*4 is 8 so we need to multiply 3.25 by 4 to get x...
3.25*4=$13
Plug in 0 for x
2*2 + (0) - 4
4 + (0) -4
0
y intercept is 0
Answer: I think that the answer would be B. This is what i got after doing the work
Her is the data of major river system in India on the basis of their pollution level:
Sabarmati :
Around 4 mg/L
On the basis of the statistics taken in 2010 are:
Markanda: 590 mg Oxygen /liter
Amlakhadi: 353 mg Oxygen /liter
Kali: 364 mg Oxygen /liter
Yamuna canal: 247 mg Oxygen /liter
The Yamuna near Delhi: 70 mg Oxygen /liter
Betwa: 58 mg Oxygen /liter
The levels of 8 mg/L or less is acceptable and below 2 mg/L is also considered as a good water.
Ganga :
At Rishikesh: 1.5 mg Oxygen/L.
At Kanpur: 5 mg/L
Brahmaputra:
At Gauhati - very high.
At other locations: 2 mg /L or less
Tapi:
In certain areas: 2 mg/L .
In cities and towns: 13 mg/L
Narmada:
Less than 2.5 mg/L
Mahanadi:
Less than 1 mg Oxygen / Litre to 4 mg Oxygen / Litre in cities or Chattisgarh
Krishna:
1 mg Oxygen / Litre to 3 mg Oxygen / Litre 10 mg Oxygen / Litre in certain cities/towns.
Pune:
Around 28 mg/L
Cauvery :
From 1 mg/L to 3 mg/L
Ganga :
From 4 mg/l to 8 mg/l
Godavari :
Around 5 mg/l
Vitharini (Bitarni) :
Around 2 mg/l
Narmada :
Around 2 mg/l
Mahi :
Around 2.5 mg//l
The correct answer would be -1/8
