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katen-ka-za [31]
3 years ago
7

The internet protocol uses unique addresses, simply called ____ addresses, to identify computers or devices in a network.

Computers and Technology
1 answer:
Nezavi [6.7K]3 years ago
3 0
IP Address, that is a unique address used to identify devices in a network
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Is a MODEM required for Internet Connectivity ?<br> Yes<br> No
Pie

Answer:

you can connect to the wifi on your device it will say you are connected but the wifi will not be connected to the internet so you will be able to do nothing on it without the modem

Explanation:

4 0
3 years ago
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Variablesallow us to manipulate data through the ___________.
gladu [14]

Answer:

Reference

Explanation:

Variables provide reference to the stored data value.

For example:

int i = 0;

Here i is a variable of type int with an initial value of 0. i is a reference to this stored value 0. Now if I want to update the data, I can do so using this reference.

i = 1;

Now the reference is used to manipulate the stored data and change it to 1. In a similar manner all updates to the value can be done using the variable reference.

8 0
3 years ago
In JAVA please:
blagie [28]

Answer:

import java.util.Scanner;

public class ArraysKeyValue {

public static void main (String [] args) {

final int SIZE_LIST = 4;

int[] keysList = new int[SIZE_LIST];

int[] itemsList = new int[SIZE_LIST];

int i;

keysList[0] = 13;

keysList[1] = 47;

keysList[2] = 71;

keysList[3] = 59;

itemsList[0] = 12;

itemsList[1] = 36;

itemsList[2] = 72;

itemsList[3] = 54;  

/* Your solution goes here */

for ( i = 0; i < SIZE_LIST; i++){

 if (keysList[i]>50){

  System.out.println(itemsList[i] + " ");  }  }

System.out.println("");

}

}

Explanation:

I will explain the whole program flow.

  • There are two arrays here
  • keysList and itemsList
  • The first list (keysList) contains the following elements:

13 element at first position of the array (0th index)

47 element at second  position of the array (1st index)

71 element at third position of the array (2nd index)

59 element at fourth position of the array (3rd index)

  • The other list (itemsList) contains the following elements:

12 element at first position of the array (0th index)

36 element at second  position of the array (1st index)

72 element at third position of the array (2nd index)

54 element at fourth position of the array (3rd index)

  • The size of the array elements is fixed which is 4 and is stored in the variable SIZE_LIST.
  • Then the loop starts. The loop contains a variable i which is initialized to 0. First it checks if the value of i is less than the size of the list. It is true as SIZE_LIST=4 and i=0.
  • So the program control enters the body of the loop.
  • In first iteration, IF condition checks if the i-th element of the keysList is greater than 50. As i=0 So the element at 0th index of the keysList is 13 which is not greater than 50 so the body of IF statement will not execute as the condition evaluates to false. The value of i increments by 1 so now i becomes 1.
  • In next iteration loop again checks if the value of i is less than the size of the list which is true again so the body of the loop executes.
  • IF condition checks if the i-th element of the keysList is greater than 50. As i=1 So the element at 1st index of the keysList is 47 which is not greater than 50 so the body of IF statement will not execute as the condition evaluates to false. The value of i is incremented by 1 so now i becomes 2.
  • In next iteration loop again checks if the value of i is less than the size of the list which is true again as i= 2 which is less than SIZE_LIST so the body of the loop executes.
  • IF condition checks if the i-th element of the keysList is greater than 50. As i=2 So the element at 2nd index of the keysList is 71 which is greater than 50 so the body of IF statement is executed as the condition evaluates to true. So in the body of the IF statement there is a print statement which prints the i-th element of the itemsList. As i = 2 so the value at the index 2 of the itemsList is displayed in the output which is 72. Next value of i is incremented by 1 so now i becomes 3.
  • In next iteration loop again checks if the value of i is less than the size of the list which is true again as i= 3 which is less than SIZE_LIST so the body of the loop executes.
  • IF condition checks if the i-th element of the keysList is greater than 50. As i=3 So the element at 3rd index of the keysList is 59 which is greater than 50 so the body of IF statement is executed as the condition evaluates to true. So in the body of the IF statement there is a print statement which prints the i-th element of the itemsList. As i = 3 so the value at the index 3 of the itemsList is displayed in the output which is 54. Next value of i is incremented by 1 so now i becomes 4.
  • In next iteration loop again checks if the value of i is less than the size of the list which is now false as i=4 which is equal to the SIZE_LIST= 4. So the loop breaks.
  • So the output of the above program is:

72

54

5 0
3 years ago
The four smallest numbers (40 points) Write an ANNA assembly program (smallest_four.ac) that finds the four smallest numbers ent
kari74 [83]

Answer:

the answer is -25

Explanation:

6 0
3 years ago
Describe two measures you can use to evaluate whether an attachment in a message is reliable to open.
meriva
<span>If a attachment is not reliable to open, terrible effects can happen, peradventure it may have a virus or even malware that can destroy a computers software. 

To avoid this and stay on the safe side, try the following:-

- Open it in protected view 
- Do not save the attachment on your computer 
- Look at the author and read the message carefully to make sure it is not biased. 
- Open it on a flash-drive </span>
8 0
3 years ago
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