Answer:
the answer would be B proxy server
Answer:
// here is code in C++
#include <bits/stdc++.h>
using namespace std;
// main function
int main()
{
// variables
int n,no_open=0;
cout<<"enter the number of lockers:";
// read the number of lockers
cin>>n;
// initialize all lockers with 0, 0 for locked and 1 for open
int lock[n]={};
// toggle the locks
// in each pass toggle every ith lock
// if open close it and vice versa
for(int i=1;i<=n;i++)
{
for(int a=0;a<n;a++)
{
if((a+1)%i==0)
{
if(lock[a]==0)
lock[a]=1;
else if(lock[a]==1)
lock[a]=0;
}
}
}
cout<<"After last pass status of all locks:"<<endl;
// print the status of all locks
for(int x=0;x<n;x++)
{
if(lock[x]==0)
{
cout<<"lock "<<x+1<<" is close."<<endl;
}
else if(lock[x]==1)
{
cout<<"lock "<<x+1<<" is open."<<endl;
// count the open locks
no_open++;
}
}
// print the open locks
cout<<"total open locks are :"<<no_open<<endl;
return 0;
}
Explanation:
First read the number of lockers from user.Create an array of size n, and make all the locks closed.Then run a for loop to toggle locks.In pass i, toggle every ith lock.If lock is open then close it and vice versa.After the last pass print the status of each lock and print count of open locks.
Output:
enter the number of lockers:9
After last pass status of all locks:
lock 1 is open.
lock 2 is close.
lock 3 is close.
lock 4 is open.
lock 5 is close.
lock 6 is close.
lock 7 is close.
lock 8 is close.
lock 9 is open.
total open locks are :3
Answer: expediting the local area network
Explanation: Case tools are the tools or service that helps in the software development but the automatic activity. This tool can be applied on various applications like mobile apps, E-commerce websites etc.
Analyst focus on the features like improving productivity ,low time consumption,integration of the work and making the communication better with the users ,helps in producing large amount of the documents etc.
The only factor not accepted by analyst is accomplishing the operation in the LAN(local area network) as it does not facilitates this operation because it is not software development process.
Answer:
The solution code is written in Java
- import java.util.Scanner;
-
- public class Main {
- public static void main (String [] args) {
-
- Scanner inStream = new Scanner(System.in);
- System.out.print("Please input a number (1 - 10): ");
- int num = inStream.nextInt();
-
- if(num < 1 || num > 10){
- System.out.println("The input must be between 1 - 10");
- }else{
- switch(num){
- case 1:
- System.out.println("I");
- break;
- case 2:
- System.out.println("II");
- break;
- case 3:
- System.out.println("III");
- break;
- case 4:
- System.out.println("IV");
- break;
- case 5:
- System.out.println("V");
- break;
- case 6:
- System.out.println("VI");
- break;
- case 7:
- System.out.println("VII");
- break;
- case 8:
- System.out.println("VIII");
- break;
- case 9:
- System.out.println("IX");
- break;
- case 10:
- System.out.println("X");
- break;
- }
- }
- }
- }
Explanation:
The first part of this program (Line 6 - 8) is to get input number from user using Scanner object. Input validation has been done to check if the input number is in the acceptable range (Line 10). If not, an error message will be displayed (Line 11).
If the input number is in the range of 1 - 10, the number will go through a series of switch statements checking. If the number meet the condition in one of the switch cases, it will print the corresponding roman numeral specified in the case block (Line 13 - 44). For example, if input number is 9, the case 9 condition is met and "IX" will be printed.
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