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solniwko [45]
4 years ago
7

How to solve it and what’s the answer ?

Mathematics
1 answer:
vova2212 [387]4 years ago
3 0
You cut both of the triangle’s out and then you make a rectangle with it and then you do it like a rectangles
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That's good foods warehouse Charlotte can buy three candy bars for $.99 also aftermarket she can buy for candy bars for $1.25 wh
erastovalidia [21]
The store where it says she can buy three candy bars for $.99
7 0
4 years ago
1 3/7 - 4/5 = <br> 1 13/35 <br> 1 22/35 <br> 13/35 <br> 22/35
joja [24]
1 3/7 - 4/5
10/7 - 4/5
(50/35) - (28/35)
(50-28)/35
22/35

The answer is 22/35
4 0
3 years ago
Read 2 more answers
How do you write in an expression The sum of c squared and fourteen
kow [346]

c² + 14

Hope this helps you!

8 0
3 years ago
What is the distance between the points (21 , 13) and (3 , 13) in the coordinate plane?
Oxana [17]

Answer:

\displaystyle d = 18

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

  • Coordinates (x, y)

<u>Algebra II</u>

  • Distance Formula: \displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

Point (21, 13)

Point (3, 13)

<u>Step 2: Find distance </u><em><u>d</u></em>

Simply plug in the 2 coordinates into the distance formula to find distance <em>d</em>

  1. Substitute in points [Distance Formula]:                                                         \displaystyle d = \sqrt{(3-21)^2+(13-13)^2}
  2. [√Radical] (Parenthesis) Subtract:                                                                   \displaystyle d = \sqrt{(-18)^2+(0)^2}
  3. [√Radical] Evaluate exponents:                                                                       \displaystyle d = \sqrt{324+0}
  4. [√Radical] Add:                                                                                                 \displaystyle d = \sqrt{324}
  5. [√Radical] Evaluate:                                                                                          \displaystyle d = 18
5 0
3 years ago
      A light plane flew from its home base to an airport 255 miles away. With a head wind, the trip took 1.7 hours. The return
ryzh [129]
The speed from home base to airport was:
v=255miles/1.7h\ /:1.7\\v=150mph
The speed from airport to home base was:
v=255miles/1.5h\ /:1.5\\v=170mph
Average speed of plane was:
\frac{170mph+150mph}{2}=160mph
Average speed of wind was:
x\ -\ wind\ speed\ (mph)\\150+x=170-x\ /+x\\150+2x=170\ /-150\\2x=20\ /:2\\x=10
Answer: Average speed of plane was 160mph and average speed of wind was 10mph.

I hope I helped :D
6 0
4 years ago
Read 2 more answers
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