All categories

4 years ago

How to solve it and what’s the answer ?

Mathematics

1 answer:

vova2212 [387]4 years ago

3 0

You cut both of the triangle’s out and then you make a rectangle with it and then you do it like a rectangles

You might be interested in

What is the measure of ∠A, to the nearest degree?<br> 17°<br> 33°<br> 57°<br> 73°

DiKsa [7]

17 I think but idk for sure

7 0

3 years ago

Read 2 more answers

Don't understand what I have to do in order to find out what I have to plot.

pochemuha

(1, 22), (3, 18), (5,14), (6, 13), (8,5)

(1, 23), (3, 18), (5,14), (6, 11), (8,7)

you plot there on a graph. do you know how to place on a graph?

if not, the line going up and down is the x-axis and the line going side to side is the y-axis,

for example (4,7) it would be (x,y)

i really hope this helps :)

3 0

3 years ago

Data were collected on the amount spent by 64 customers for lunch at a major Houston restaurant. These data are contained in the

galina1969 [7]

Answer:

a. The margin of error is 2.29.

b. 19.23 to 23.81

Step-by-step explanation:

The sample size is n=64.

We start by calculating the sample mean and standard deviation with the following formulas:

$M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\s=\sqrt{\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M)^2}$

The sample mean is M=21.52.

The sample standard deviation is s=6.89.

We have to calculate a 99% confidence interval for the mean.

The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.

When σ is not known, s divided by the square root of N is used as an estimate of σM:

$s_M=\dfrac{s}{\sqrt{N}}=\dfrac{6.89}{\sqrt{64}}=\dfrac{6.89}{8}=0.861$

The degrees of freedom for this sample size are:

$df=n-1=64-1=63$

The t-value for a 99% confidence interval and 63 degrees of freedom is t=2.656.

The margin of error (MOE) can be calculated as:

$MOE=t\cdot s_M=2.656 \cdot 0.861=2.29$

Then, the lower and upper bounds of the confidence interval are:

LL=M-t \cdot s_M = 21.52-2.29=19.23\\\\UL=M+t \cdot s_M = 21.52+2.29=23.81

The 99% confidence interval for the mean is (19.23, 23.81).

5 0

3 years ago

On a number line, suppose point E has a coordinate of 2, and EGequals5. What are the possible coordinates of point G?

Ivan

Answer:

-3, 7

Step-by-step explanation:

EG = 5, so the distance between E and G is five.

G can be 5 units to the right of E:

2 + 5 = 7

G has coordinate 7.

G can be 5 units to the left of E:

2 - 5 = -3

G has coordinate -3.

Answer: -3, 7

6 0

3 years ago

A) 18/3 + 2 x 8-7 solve

svet-max [94.6K]

Answer:

Step-by-step explanation:

i believe the answer is 15

5 0

3 years ago

Read 2 more answers