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s2008m [1.1K]
3 years ago
11

What is the distance between the points (21 , 13) and (3 , 13) in the coordinate plane?

Mathematics
1 answer:
Oxana [17]3 years ago
5 0

Answer:

\displaystyle d = 18

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

  • Coordinates (x, y)

<u>Algebra II</u>

  • Distance Formula: \displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

Point (21, 13)

Point (3, 13)

<u>Step 2: Find distance </u><em><u>d</u></em>

Simply plug in the 2 coordinates into the distance formula to find distance <em>d</em>

  1. Substitute in points [Distance Formula]:                                                         \displaystyle d = \sqrt{(3-21)^2+(13-13)^2}
  2. [√Radical] (Parenthesis) Subtract:                                                                   \displaystyle d = \sqrt{(-18)^2+(0)^2}
  3. [√Radical] Evaluate exponents:                                                                       \displaystyle d = \sqrt{324+0}
  4. [√Radical] Add:                                                                                                 \displaystyle d = \sqrt{324}
  5. [√Radical] Evaluate:                                                                                          \displaystyle d = 18
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Step-by-step explanation:

Since b1 is equal to 14 yds and b2 is equal to 26 yds we can plug that into the equation below (in the image).

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In a lot of area equations, you will have to divide by two like in the trapezoid equation. Divide our number (600) by 2, so we get 600 ÷ 2 = 300.

300 yds is your final answer.

Hope this helps!

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Answer:

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Step-by-step explanation:

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