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ad-work [718]
3 years ago
14

In the figure, is divided into equal parts. The coordinates of point A are (2, 4), and the coordinates of point B are (10, 6). M

atch each pair of coordinates to the corresponding point on .

Mathematics
1 answer:
timofeeve [1]3 years ago
8 0

Answer:

Step-by-step explanation:

We will use mid point formula:

According to the attached picture:

F is the mid point of A and B.

Thus by using formula we have,

F = (2+10)/2 , (4+6)/2

= 12/2 , 10,2

= 6,5

F should be (6,5)

Like wise the matched coordinates are:

D is the midpoint of A and F and is (4,4.5)

C is the midpoint of A and D and is (3,4.25)

E is the mid point of D and F and is (5,4.75)

H is the midpoint of F and B and is (8,5.5)

G is the midpoint of F and H and is (7, 5.25)

I is the midpoint of H and B and is (9,5.75) ....

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andrezito [222]

Answer:

r = 144 units

Step-by-step explanation:

The given curve corresponds to a parametric function in which the Cartesian coordinates are written in terms of a parameter "t". In that sense, any change in x can also change in y owing to this direct relationship with "t". To find the length of the curve is useful the following expression;

r(t)=\int\limits^a_b ({r`)^2 \, dt =\int\limits^b_a \sqrt{((\frac{dx}{dt} )^2 +\frac{dy}{dt} )^2)}     dt

In agreement with the given data from the exercise, the length of the curve is found in between two points, namely 0 < t < 16. In that case a=0 and b=16. The concept of the integral involves the sum of different areas at between the interval points, although this technique is powerful, it would be more convenient to use the integral notation written above.

Substituting the terms of the equation and the derivative of r´, as follows,

r(t)= \int\limits^b_a \sqrt{((\frac{d((1/2)t^2)}{dt} )^2 +\frac{d((1/3)(2t+1)^{3/2})}{dt} )^2)}     dt

Doing the operations inside of the brackets the derivatives are:

1 ) (\frac{d((1/2)t^2)}{dt} )^2= t^2

2) \frac{(d(1/3)(2t+1)^{3/2})}{dt} )^2=2t+1

Entering these values of the integral is

r(t)= \int\limits^{16}_{0}  \sqrt{t^2 +2t+1}     dt

It is possible to factorize the quadratic function and the integral can reduced as,

r(t)= \int\limits^{16}_{0} (t+1)  dt= \frac{t^2}{2} + t

Thus, evaluate from 0 to 16

\frac{16^2}{2} + 16

The value is r= 144 units

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Answer:

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Step-by-step explanation:

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Solve the rational equation 1/n-4 - 2/n = 3/4-n
Leokris [45]

Answer:

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Step-by-step explanation:

Given equation: \[\frac{1}{n-4}-\frac{2}{n}=\frac{3}{4-n}\]

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=> \[(8-n)*(4-n) =n*(n-4)*3\]

=> \[n-8 =3n\]

=> \[2n =8\]

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