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4 years ago

Determine whether 606 is divisible by 2, 3, 4, or 6.

Mathematics

2 answers:

alexgriva [62]4 years ago

7 0

$606/2=303 \\ 
 \\ 606/3=202 \\ 
 \\ 606/4=151.5 \\ 
 \\ 606/6=101 \\ 
 \\ Answer:C.2,3 \ and \ 6 \ only \\$

Anvisha [2.4K]4 years ago

5 0

We can already eliminate A, since if it is divisible by 2 and 3, it is automatically divisible by 6.
We can eliminate B since if it is divisible by 6, it must be divisible by 2.
We can eliminate D since to figure out whether a number is divisible by 4, you keep the last two place values ( in this case 06 which is not divisible by 4.)

Therefore, by process of elimination, the answer is C

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Is (0,-2) a solution of x + y = 6? Click on the correct answer?

goldenfox [79]

Answer:That is not the solution explanation: because if you put the 0 in place of the x in the equation, y would have to equal 6. If you put the -2 in place of the y then x would have to equal 8.
Simpler explanation: 0 + -2 = -2 not 6

6 0

4 years ago

Michael baked 60 oatmeal cookies and 45 chocolate chip cookies to package in plastic containers for her friends at school. She w

Scrat [10]

Answer:

Step-by-step explanation:

Michael must find the smallest number possible that can divide 60 and 45 then take the two quotients after dividing the 2 types of cookies by the smallest number possible.

2 is not possible as 45 is an odd number

3 can divide both 60 and 45

60/3 = 20 oatmeal cookies in each container.

45/3 = 15 chocolate chip cookies in each container.

7 0

3 years ago

Triangle J K L is shown. Angle J K L is 120 degrees and angle K L J is 40 degrees. The length of K L is 2 and the length of J L

Veseljchak [2.6K]

Answer:

$k \approx 5$ units$

Step-by-step explanation:

In Triangle JKL

$\angle K=120^\circ\\\angle L=40^\circ\\KL=2\\JL=k$

We want to determine the approximate value of k using the law of sines.

$\angle J+\angle K+\angle L=180^\circ $ (Sum of angles in a \triangle)\\\angle J+120^\circ+40^\circ=180^\circ \\\angle J=180^\circ-(120^\circ+40^\circ)=20^\circ$

Using Law of Sines

$\dfrac{k}{\sin K} =\dfrac{j}{\sin J} \\\dfrac{k}{\sin 120} =\dfrac{2}{\sin 20} \\k=\sin 120 \times \dfrac{2}{\sin 20}\\k=5.06\\k \approx 5$ units$

7 0

3 years ago

Read 2 more answers

The set of ordered pairs below represents a relation that is a function.

swat32

Answer:

I'm confused by the points:

Why three points for each (A, B, C, and D)?: A: (0,6)(0,6)(0,6), etc.

Points A and B [(0,6) and (4,2)] are consistant with a straight line of the form y=-x+6.

Points C and D [(-6,8),(-8,10)]are on the line y=-x+2.

A and B aren't related to C and D.

Step-by-step explanation:

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3 years ago

Compare and contrast division property of equality and inequality

ch4aika [34]

The two properties are exactly the same when dividing by a positive number. For the division property of equality, dividing by a negative number causes the equal sign to change. Dividing both sides of an inequality by a negative number does not have an effect on the relation symbol.

7 0

4 years ago