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3 years ago

Isolate the variable x. - 5x < 10

Mathematics

1 answer:

Neporo4naja [7]3 years ago

8 0

Answer:

x > - 2

x ∈ ( - 2 ; + oo)

Step-by-step explanation:

- 5x < 10 | *(-)

5x > - 10 | : 2

x > - 2

x ∈ ( - 2 ; + oo)

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Find the area of the polygon

AlekseyPX

Answer:

The answer is $383m^{2}$ .

To find the area of a rectangle, we multiply the length of the rectangle by the width of the rectangle.

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3 years ago

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Anastaziya [24]

Answer:

C and D

Step-by-step explanation:

D. A negative times a positive gives you a negative, so the first 2 fractions will still be negatives after they get out of the parenthesis

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3 years ago

Read 2 more answers

A rhombus has its diagonals 7cm and 6 cm whats its area

ipn [44]

$\large\frak{ Given :}$

Diagonal of a rhombus = 7 cm and 6 cm

$\large\frak{Find:}$

Area of a rhombus

$\large\frak{Explanation :}$

$\small\tt Area = \frac{1}{2}× d¹ × d²$

Where,

d¹ = length of diagonal 1
d² = length of diagonal 2

$\implies \small\tt{ \frac{1}{2} \times 7 \times 6}$

$\implies\small\tt{ \frac{1}{2} \times 42 }$

$\implies \small\tt{Area = 21 {cm}^{2} }$

5 0

2 years ago

Find the sample size necessary to estimate the mean IQ score of statistics students such that it can be said with 99% confidenc

quester [9]

Answer: 18

Step-by-step explanation:

The formula to find the minimum sample size is given by :_

$n=(\dfrac{z^*\cdot \sigma}{E})^2$

, where $\sigma$ = population standard deviation.

z*= critical z-value.

E= Margin of error.

Given : $\sigma= 13$

E= ± 8

We know that critical value corresponding to 99% confidence level = z*=2.576 [Using z-table]

Then, the required sample size would be :

$n=(\dfrac{(2.576)\cdot (13)}{8})^2$

$\Rightarrow\ n=(4.186)^2$

$\Rightarrow\ n=17.522596\approx18$ [Round to next integer.]

Hence, the required minimum sample size = 18

4 0

4 years ago

Maximize the objective function P = 2x + 1.5y for the feasible region shown. State the maximum value for P and the ordered pair

umka2103 [35]

Incomplete question. However, let's assume this are feasible regions to consider:

Points:

- (0, 100)

- (0, 125)

- (0, 325)

- (1, 200)

Answer:

Maximum value occurs at 325 at the point (0, 325)

Step-by-step explanation:

Remember, we substitute the points value for x, y in the objective function P = 2x + 1.5y.

- For point (0, 100): P= 2(0) + 1.5 (100) =150

- For point (0, 125): P= 2(0) + 1.5 (125) =187.5

For point (0, 325): P= 2(0) + 1.5 (325) = 487.5

For point (1, 200): P= 2(1) + 1.5 (200) = 302

Therefore, we could notice from the above solutions that at point (0,325) we attain the maximum value of P.

7 0

3 years ago