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3 years ago

The graph of an absolute value function opens up and has a vertex of (0, -3).

Mathematics

1 answer:

Anit [1.1K]3 years ago

4 0

Answer:

The domain: all real numbers;

The range: $y\ge -3.$

Step-by-step explanation:

The graph of the function y=|x| opens up and has a vertex at (0,0). If the graph of an absolute value function opens up and has a vertex of (0, -3), then the function has an expression

y=|x|-3 (see attached diagram).

The domain of the parent function y=|x| is the set of all real numbers, then the domain of the function y=|x|-3 is the set of all real numbers too.

The range of the parent function y=|x| is $y\ge 0,$ then the range of the function y=|x|-3 is $y\ge -3.$

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elena-s [515]

I believe that is 120

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2 years ago

The Polygons below are similar find the value of x and y

balandron [24]

Answer:

$x=49\degree,y=6$

Step-by-step explanation:

Angle $x$ corresponds to the complement of the $41\degree$ in the bigger triangle. See diagram in attachment.

This implies that,

$x=90-41=49\degree$

Also since the triangles are similar, the sides are in the same proportion.

This implies that,

$\frac{3y-8}{15}=\frac{4}{6}$

We multiply both sides by 15 to get,

$3y-8=\frac{4}{6}\times 15$

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$\Rightarrow 3y-8=10$

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The correct answer is D

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3 years ago

The student body of a large university consists of 60% female students. A random sample of 8 students is selected. Refer to Exhi

jasenka [17]

Answer:

0.0499

Step-by-step explanation:

This is a binomial probability function expressed as:

$P(X=x)={n\choose x}p^x(1-p)^{n-x}\\\\$

Given that n =8, and p(male)=1-0.6=0.4, the probability of at least 6 being male is calculated as:

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3 years ago

100 points!!!

Bogdan [553]

Answer:

(1, 5)

Step-by-step explanation:

The solution to the system of equations is the point of intersection of the two lines. From inspection of the graph, the point of intersection is at (1, 5).

<u>Proof</u>

The solution to a system of equations is the point at which the two lines meet.

⇒ g(x) = f(x)

⇒ 3x + 2 = |x - 4| + 2

⇒ 3x = |x - 4|

⇒ 3x = x - 4 and 3x = -(x - 4)

⇒ 3x = x - 4

⇒ 2x = -4

⇒ x = -2

Inputting x = -2 into the 2 equations:

⇒ g(-2) = 3 · -2 + 2 = -4

⇒ f(-2) = |-2 - 4| + 2 = 8

Therefore, as the y-values are different, x = -2 is NOT a solution

⇒ 3x = -(x - 4)

⇒ 3x = 4 - x

⇒ 4x = 4

⇒ x = 1

Inputting x = 1 into the 2 equations:

⇒ g(1) = 3 · 1 + 2 = 5

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Therefore, as the y-values are the same, x = 1 IS a solution

and the solution is (1, 5)

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2 years ago

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3 years ago