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DIA [1.3K]
3 years ago
13

Solve for n: 21k − 3n + 9p > 3p + 12

Mathematics
2 answers:
Vlad1618 [11]3 years ago
8 0

Answer:

n<2p-4+7k

Step-by-step explanation:

abruzzese [7]3 years ago
7 0

Answer:

n < 2p + 7k - 4

Step-by-step explanation:

Isolate the variable, n. Do the opposite of PEMDAS. Treat the > like an equal sign, what you do to one side, you do to the other.

First, subtract 21k and 9p from both sides:

21k (-21k) - 3n + 9p (-9p) > 3p (-9p) + 12 (-21k)

-3n > (3p - 9p) - 21k + 12

Simplify. Combine like terms:

-3n > (3p - 9p) - 21k + 12

-3n > (-6p) - 21k + 12

-3n > -6p - 21k + 12

Isolate the variable, n. Note that when you divide by -3, you divide from all terms, and you flip the sign:

(-3n)/-3 > (-6p - 21k + 12)/-3

n < (-6p - 21k + 12)/-3

n < (-6p)/-3 + (-21k)/-3 + (12/-3)

n < 2p + 7k - 4

n < 2p + 7k - 4 is your answer.

~

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Answer: 5 1/2 hours

Step-by-step explanation:

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Hope this helps!

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Solve for b2 in A = 1/2 h ( b1 + b2 ), if A = 16, h = 4, and b1 = 3.
Katarina [22]

Hello from MrBillDoesMath!

Answer:

b2 = 5  


Discussion:

A = 1/2 h (b1 + b2) .

Substituting A = 16, h = 4, and b1=3 in the above formula gives:

16 = (1/2) (4)( 3 + b2)    =>         (as (1/2)4 = 2) )

16 = 2 ( 3 + b2)             =>         (divide both sides by 2)

8 = (3 + b2)                   =>         (subtract 3 from both sides)

8-3  = b2                       =>

5     =  b2


Check Area formula:

Does A = 16 = (1/2)(4)(3+5)   ?

Does 16 = (1/2) (4)(8)             ?

Does 16 = (1/2)(32)                ?  Yes it does so our calculation for b2 is correct




Thank you,

MrB

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