All categories

3 years ago

Solve for n: 21k − 3n + 9p > 3p + 12

Mathematics

2 answers:

Vlad1618 [11]3 years ago

8 0

Answer:

n<2p-4+7k

Step-by-step explanation:

abruzzese [7]3 years ago

7 0

Answer:

n < 2p + 7k - 4

Step-by-step explanation:

Isolate the variable, n. Do the opposite of PEMDAS. Treat the > like an equal sign, what you do to one side, you do to the other.

First, subtract 21k and 9p from both sides:

21k (-21k) - 3n + 9p (-9p) > 3p (-9p) + 12 (-21k)

-3n > (3p - 9p) - 21k + 12

Simplify. Combine like terms:

-3n > (3p - 9p) - 21k + 12

-3n > (-6p) - 21k + 12

-3n > -6p - 21k + 12

Isolate the variable, n. Note that when you divide by -3, you divide from all terms, and you flip the sign:

(-3n)/-3 > (-6p - 21k + 12)/-3

n < (-6p - 21k + 12)/-3

n < (-6p)/-3 + (-21k)/-3 + (12/-3)

n < 2p + 7k - 4

n < 2p + 7k - 4 is your answer.

You might be interested in

Please help quickly.<br> Find the measure of the unknown angle

Vladimir [108]

Answer:

Step-by-step explanation:

yessss

5 0

2 years ago

Read 2 more answers

Identify the expression with nonnegative limit values. More info on the pic. PLEASE HELP.

marshall27 [118]

Answer:

$\lim _{x\to 2}\:\frac{x-2}{x^2-2}\\\\ \lim _{x\to 11}\:\frac{x^2+6x-187}{x^2+3x-154}\\\\ \lim _{x\to \frac{5}{2}}\left\frac{2x^2+x-15}{2x-5}\right$

Step-by-step explanation:

a) $\lim _{x\to 3}\:\frac{x^2-10x+21}{x^2+4x-21}=\lim \:_{x\to \:3}\:\frac{\left(x-7\right)\left(x-3\right)}{\left(x+7\right)\left(x-3\right)}=\lim \:_{x\to \:3}\:\frac{x-7}{x+7}=\frac{3-7}{3+7}=-\frac{4}{10}=-\frac{2}{5}$

b) $\lim _{x\to -\frac{3}{2}}\left(\frac{2x^2-5x-12}{2x+3}\right)=\lim \:_{x\to -\frac{3}{2}}\:\frac{\left(2x+3\right)\left(x-4\right)}{\left(2x+3\right)}=\lim \:\:_{x\to \:-\frac{3}{2}}\:\left(x-4\right)=-\frac{3}{2}-4\\ \\ \lim _{x\to -\frac{3}{2}}\left(\frac{2x^2-5x-12}{2x+3}\right)=-\frac{11}{2}$

c) $\lim _{x\to 2}\:\frac{x-2}{x^2-2}=\frac{2-2}{\left(2\right)^2-2}=\frac{0}{4-2}=0$

d) $\lim _{x\to 11}\:\frac{x^2+6x-187}{x^2+3x-154}=\lim _{x\to 11}\:\frac{\left(x-11\right)\left(x+17\right)}{\left(x-11\right)\left(x+14\right)}=\lim _{x\to 11}\:\frac{\left(x+17\right)}{\left(x+14\right)}=\frac{11+17}{11+14}=\frac{28}{25}$

e) $\lim _{x\to 3}\:\frac{x^2-8x+15}{x-3}=\lim \:_{x\to \:3}\:\frac{\left(x-3\right)\left(x-5\right)}{x-3}=\lim _{x\to 3}\left(x-5\right)=3-5=-2$

f) $\lim _{x\to \frac{5}{2}}\left(\frac{2x^2+x-15}{2x-5}\right)=\lim \:_{x\to \:\frac{5}{2}}\frac{\left(2x-5\right)\left(x+3\right)}{2x-5}=\lim \:\:_{x\to \:\:\frac{5}{2}}\left(x+3\right)=\frac{5}{2}+3=\frac{11}{2}$

4 0

3 years ago

A circular mirror is surrounded by a square metal frame. The radius mirror is 6x the side length of the medal frame is 18x. What

wolverine [178]

Answer:

Step-by-step explanation:

Given:

Radius of circular mirror, r = 6x

Length of metal frame, l = 18x

Area of square, As = l^2

Area of square = 18x × 18x

= 324 x^2.

Area of circular mirror, Ac = pi × r^2

= π × (6x)^2

= 36π x^2.

The expression for the area of the frame is subtracting the mirror from the metal frame = As - Ac

= 324x^2 - 36πx^2

= 36x2 (9 - π).

4 0

3 years ago

Read 2 more answers

The table shows the relationship y = kx.

sammy [17]

Answer: it’s 1/5

Step-by-step explanation:

6 0

3 years ago

What is the total time it will take the snowball to melt completely

podryga [215]

Point-slope form

y -24 = -4/5(x -0)

Find x when y is 0 (X-intercept)

0 -24 = -4/5(x -0)

-24 = -4/5x

x = -120/-4

x = 30

Answer: A. 30 minutes

5 0

3 years ago