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4vir4ik [10]
3 years ago
13

A blue suit case weighs 10 pounds less than three fourths the weight of a green suitcase.Write an expression that you can use to

find the weight of the blue suitcase.Then explain how you can find the total weight of both suitcases if the green suitcase weighs 36 pounds.
Mathematics
1 answer:
Readme [11.4K]3 years ago
6 0

Answer:

The total weight of both suitcases is 53 pounds.

Step-by-step explanation:

Write an expression that you can use to find the weight of the blue suitcase.

b = 3/4 * g - 10

Then explain how you can find the total weight of both suitcases if the green suitcase weighs 36 pounds.

b + g = 3/4 * g - 10 + g = 7/4 * g - 10 = 7/4 * 36 - 10 = 53 pounds

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What is the value of x?
pochemuha

Answer:

14

Step-by-step explanation:

We can use the Pythagorean theorem since this is a right triangle.

a^2 +b^2 = c^2

where a and b are the legs and c is the hypotenuse

x^2 + 48^2 = 50^2

x^2 +2304=2500

Subtract 2304 from each side

x^2 +2304-2304=2500-2304

x^2 =196

Take the square root of each side

sqrt(x^2) =sqrt(196)

x =14

3 0
3 years ago
Read 2 more answers
156, 153, 150, ...<br> Find the 30th term.
Maksim231197 [3]

Answer:

First multiply 30 by 3 = 90 then subtract 90 from 156 to get 66

Step-by-step explanation:

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3 0
3 years ago
1] If 221ₓ= 25₁₀ find X<br> 2] if 3ₓ + 34ₓ - 40ₓ = 0 find x<br> 3] if 23ₓ = 1111₂ find x
Olin [163]

1.

2\cdot x^2+2\cdot x^1+1\cdot x^0=25\\2x^2+2x+1=25\\2x^2+2x-24=0\\x^2+x-12=0\\x^2+4x-3x-12=0\\x(x+4)-3(x+4)=0\\(x-3)(x+4)=0\\x=3 \vee x=-4

The base can't be negative, therefore x=3.

2.

3\cdot x^0+3\cdot x^1+4\cdot x^0-4\cdot x^1+0\cdot x^0=0\\3+3x+4-4x=0\\x=7

3.

2\cdot x^1+3\cdotx^0=1\cdot 2^3+1\cdot2^2+1\cdot2^1+1\cdot2^0\\2x+1=8+4+2+1\\2x=14\\x=7

5 0
2 years ago
Really need help on this guys!
Sergio039 [100]
<h2>Hello!</h2>

The answer is:

The center of the circle is the point (-9,-2) and the circle has a radius of 6 units.

<h2>Why?</h2>

To solve the problem, we need to use the given equation which is in the general form, and then, use it transform it to the standard form in order to find the center of the circle and its radius.

So,

We are given the circle:

x^{2}+y^{2}+18x+4y+49=0

We know that a circle can be written in the following form:

(x-h)^{2}+(y-k)^{2}=r^{2}

Where,

h is the x-coordinate of the center of the circle

k is the y-coordinate of the center of the circle

r is the radius of the circle.

So, to find the center and the radius, we need to perform the following steps:

- Moving the constant to the other side of the equation:

x^{2}+y^{2}+18x+4y=-49

- Grouping the terms (x and y):

x^{2}+18x+y^{2}+4y=-49

- Completing squares for both variables, we have:

We need to sum to each side of the equation the following term:

(\frac{b}{2})^{2}

Where, b, for this case, will the coefficients for both terms that have linear variables (x and y)

So, the variable "x", we have:

x^{2} +18x

Where,

b=18

Then,

(\frac{18}{2})^{2}=(9)^{2}=81

So, we need to add the number 81 to each side of the circle equation.

Now, for the variable "y", we have:

y^{2} +4y

Where,

b=4

(\frac{4}{2})^{2}=(2)^{2}=4

So, we need to add the number 4 to each side of the circle equation.

Therefore, we have:

(x^{2}+18x+81)+(y^{2}+4y+4)=-49+81+4

Then, factoring, we have that the expression will be:

(x+9)^{2}+(y+2)^{2}=36

- Writing the standard form of the circle:

Now,  from the simplified expression (after factoring), we can write the circle in the standard form:

(x+9)^{2}+(y+2)^{2}=36

Is also equal to:

(x-(-9))^{2}+(y-(-2))^{2}=36

Where,

h=-9\\k=-2\\r=\sqrt{36}=6

Hence, the center of the circle is the point (-9,-2) and the circle has a radius of 6 units.

Have a nice day!

4 0
4 years ago
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sveta [45]
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