Answer:
Step-by-step explanation:
Which Method Should Be Used to Solve a Quadratic Equation? Quadratic equations are of the form ax2 + bx + c = 0 where a, b and c are real numbers, a ≠ 0. Quadratic equations have two solutions, but it is possible that one solution may repeat. happy to help
Answer:
Step-by-step explanation:
Eight
590 = 1800 e^(-0.4t) Divide by 1800
0.32778 = e^(-0.4t) Put the value for e in the denominator.
0.32778 = 1 / e^(0.4t) Notice the sign's gone. Multiply both sides by e^(0.4t)
0.32778 *e^(0.4t) = 1 Divide by 0.32778
e^(0.4t) = 3.0508 Take the natural log of both sides.
0.4t = 1.11542 Divide both sides by 0.4
t = 2.78855
You should put this in the original equation to see if it checks. It does.
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Nine
3^(3 - 3x) + 6 = 42 Subtract 6 from both sides
3^(3 - 3x) = 36 Take the log of both sides.
(3 - 3x) ln(3) = ln 36
(3 - 3x) *1.098612 = 3.58352 Divide by 1.098612
3 - 3x = 3.26186 Subtract 3 from both sides
- 3x = 0.26186 Divide by - 3
x = - 0.087287
Answer:
640 dm
Step-by-step explanation:
200+40+400=640dm
Answer:
x=2(twice)
y=0(twice)
Step-by-step explanation:
This question can be solved using substitution method
So let's solve
y=x+2....(1)
y=x2+5x+6....(2)
Substitute (1) into(2)
X+2=x2+5x+6
Collect like terms
X2+5x-x+6-2=0
X2+4x+4=0
X2+2x+2x+4=0
X(x+2)+2(x+2)=0
(X+2)(x+2)=0
X+2=0
Substrate 2 from both sides
X=-2
X+2=0
X=-2
Let's substitute the value of x into (1)
y=x+2
y=-2+2
Y=0(twice)
The area of a circle in terms of the circle's radius
is
Differentiating both sides with respect to
, you get
