Answer:
96
Step-by-step explanation:
The length of the large rectangle is: 5 units
The width of the large rectangle is: 7 units
- > Area of the large rectangle = length × width = 7*5 = 35 square units
The length of the middle rectangle is: 7 units
The width of the middle rectangle is: 4 units
- > Area of the middle rectangle = length × width = 7*4 = 28 square units
The length of the small rectangle is: 7 units
The width of the small rectangle is: 3 units
- > Area of the small rectangle = length × width = 7*3 = 21 square units
Area of top and the bottom triangles =2* 1/2(bh) = 4*3 = 12 square units
Then we find the total surface surface area by adding up all of these
- > 35 + 28 + 21 + 12 = 96 square units
Answer:
7 (Seven)
Step-by-step explanation:
Given information;
am an odd number;
Considering the first set of number 1,3,5,7,9 all spelt as one, three, five, seven, and nine respectively
The only odd number from the above list from which the word even can be formed from is 7 spelt as seven.
If the letter s is taken from seven, you are left with even. Hence the number is 7.
What number am i? 7 (Seven)
It would be 46 for the salary and for the income would be 35 because if u subtract that and then divide it u get 50
Answer:
There is a 0.058% probability that this student will pass the examination.
Step-by-step explanation:
For each question, there are only two possible outcomes. Either it is correct, or it is wrong. This means that we can solve this problem using the binomial probability distribution.
Binomial probability distribution:
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which is the number of different combinatios of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
In this problem
There are 12 questions, so .
The student guesses each question. There are five possible answers, only one which is correct, so .
What is the probability that a student who guesses at random on each question will pass the examination?
This is
So
There is a 0.058% probability that this student will pass the examination.