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Shkiper50 [21]
4 years ago
15

In quadrilateral PQRS, PQ= 4x-15, QR=4x+20, RS=3x+5 and SP=6x-20. What vale of x verifies that quadrilateral PQRS is a parallelo

gram
Mathematics
1 answer:
Anettt [7]4 years ago
6 0

Answer:

THE VALUE OF x = 20 ;

Step-by-step explanation:

Since the quadrilateral PQRS is parallelogram,

Opposite sides are congruent , i.e QR =PS & PQ = RS

NOW EQUATING THE SIDES,

⇒ 4x - 15 = 3x +5

⇒ x = 20

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Use the formula a2 – b2 = (a b)(a – b) to factor completely. what are the factors of 36x8 – 49? (9x4 – 1)(4x2 49) (36x4 – 7)(x2
zimovet [89]

The factors of 36x^8 – 49 are  (6x^4-7)(6x^4+7).

We are given to factor the following polynomial completely:

36x^8 – 49.

We have to find the complete factor of the given polynomial.

Completely factor means to continuously factor terms until they are in simple terms, meaning you are no longer able to factor

<h3>What is the formula for (a^2-b^2)?</h3>

The formula for (a^2-b^2)= (a+b) (a-b).

Therefore applying the given formula we have,

F=(6x^4)^2-7^2

F=(6x^4)^2-7^2\\F=((6x^4)-7)(6x^4)+7)

Thus, the required factors are

F=((6x^4)-7)(6x^4)+7)

Therefore,option (C) is correct.

To learn more about factors visit:

brainly.com/question/25829061

7 0
2 years ago
In this diagram, ABAC – AEDF. If the<br> area of ABAC = 6 in?, what is the<br> area of AEDF?
shepuryov [24]

Answer:

2.7 in²

Step-by-step explanation:

similar triangles have the same angles, and all side lengths (or other distances) of one triangle have the same scaling factor to the side lengths of the other triangle.

so, we know the relation between the 2 baselines is 2/3, as this is the factor to turn the baseline of the large triangle into the baseline of the smaller triangle.

in other words

EF = BC × 2/3

2 = 3 × 2/3

correct

how do we calculate the area of a triangle ?

Area = baseline × height / 2

from BAC we know

Area = 6

baseline = 3

height = ?

6 = 3 × height / 2

12 = 3 × height

height = 4

aha !

now, EDF has a height too that we need to calculate is Area. and this height has the same scaling factor compared to the larger triangle as the side lengths : 2/3

so, for EDF we know

Area = ?

baseline = 2

height = 4 × 2/3 = 8/3

therefore, the area is

Area = (2 × 8/3) / 2 = (16/3) / 2 = 8/3 = 2.66666... ≈ 2.7

the shirt answer would be :

we know from the 2 baselines that the scaling factor for each distance is 2/3.

for the area we need to multiply 2 distances, so that means we have to multiply both by 2/3. and so on the formula for the area we have to use 2/3 × 2/3.

2/3 × 2/3 = 4/9

=>

Area small = Area large × 4/9 = 6 × 4/9 = 24/9 = 8/3 ≈ 2.7

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3 years ago
If a measured distance of 10 inches on your map represents an actual distance of 20 miles, what is the fractional scale of the m
kirza4 [7]
2:1 is the answer! ....................
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3 years ago
Find the value of x in each of the following
skelet666 [1.2K]
A) 2x-7=13
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6 0
3 years ago
Please help i beg i never get these right
Anuta_ua [19.1K]

Answer:

\sin(105) = \frac{\sqrt 2 + \sqrt 6}{4}

Step-by-step explanation:

Given

\sin(105^o)

Required

Solve

Using sine rule, we have:

\sin(A + B) = \sin(A)\cos(B) + \sin(B)\cos(A)

This gives:

\sin(105^o) = \sin(60 + 45)

So, we have:

\sin(60 + 45) = \sin(60)\cos(45) + \sin(45)\cos(60)

In radical forms, we have:

\sin(60 + 45) = \frac{\sqrt 3}{2} * \frac{\sqrt 2}{2} + \frac{\sqrt 2}{2} * \frac{1}{2}

\sin(60 + 45) = \frac{\sqrt 6}{4} + \frac{\sqrt 2}{4}

Take LCM

\sin(60 + 45) = \frac{\sqrt 6 + \sqrt 2}{4}

Rewrite as:

\sin(60 + 45) = \frac{\sqrt 2 + \sqrt 6}{4}

Hence:

\sin(105) = \frac{\sqrt 2 + \sqrt 6}{4}

3 0
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