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Genrish500 [490]
3 years ago
10

A store pays $20 for a hat. to make a profit the store prices the hat 60% higher. later a sale reduce the price by 10%. finally,

a clearance sale reduces the sale price by 40%. what is the clearance price?
Mathematics
1 answer:
Maslowich3 years ago
6 0

The clearance price of hat is $17.28

Step-by-step explanation:

Price paid by store = $20

Increment = 60% of price paid

Increment = \frac{60}{100}*20 = \frac{1200}{100}

Increment = $12

Increased price = 20+12 = $32

Sale = 10%

Discount amount = 10% of increased price

Discount amount = \frac{10}{100}*32=\frac{320}{100}

Discount amount = $3.2

Sale price = 32 - 3.2 = $28.8

Clearance sale = 40%

Discount of clearance sale = 40% of sale price

Discount = \frac{40}{100}*28.8=\frac{1152}{100}

Discount = $11.52

Clearance price = sale price - Discount of clearance sale

Clearance price = 28.8 - 11.52 = $17.28

The clearance price of hat is $17.28

Keywords: percentage, subtraction

Learn more about subtraction at:

  • brainly.com/question/729447
  • brainly.com/question/7297385

#LearnwithBrainly

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spayn [35]

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Step-by-step explanation:

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3 years ago
R is the interior of angle TUV. The measure of RUV=30degrees, the measure of TUV=3x+16, and the measure of TUR=x+10. Find x and
choli [55]

Given

R is the interior of ∠ TUV.

m∠ RUV=30degrees, m∠ TUV=3x+16, and m∠ TUR=x+10.

Find the value of x and the m ∠TUV.

To proof

As given in the question

m ∠TUV=3x+16, and m ∠TUR=x+10

thus

m∠ RUV =  m∠ TUV - m∠ TUR

            = 3x + 16 - x -10

            = 2x + 6

As given

m ∠RUV=30°

compare both the values

we get

30 = 2x + 6

24 = 2x

12 = x

put this value in the m ∠TUV= 3x+16

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Hence proved


7 0
3 years ago
An envelope contains three cards: a black card that is black on both sides, a white card that is white on both sides, and a mixe
Over [174]

Answer:

There is a  2/3  probability that the other side is also black.

Step-by-step explanation:

Here let B1: Event of picking a card that has a black side

B2: Event of picking a card that has BOTH black side.

Now, by the CONDITIONAL PROBABILITY:

P(B_2/B_1 )  = \frac{P(B_1\cap B_2)}{P(B_1)}

Now, as EXACTLY ONE CARD has both sides BLACK in three cards.

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Also, Out if total 6 sides of cards, 3 are BLACK from one side.

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Putting these values in the formula, we get:

P(B_2/B_1 )  = \frac{P(B_1\cap B_2)}{P(B_1)} = \frac{1}{3}  \times\frac{2}{1} = \frac{2}{3}

⇒ P (B2 / B1)  =  2/3

Hence, there is a  2/3  probability that the other side is also black.

 

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olga nikolaevna [1]

Answer:

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7 0
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What is the slope of LaTeX: f\left(x\right)=3x-1
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