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Genrish500 [490]

2 years ago

10

A store pays $20 for a hat. to make a profit the store prices the hat 60% higher. later a sale reduce the price by 10%. finally,

a clearance sale reduces the sale price by 40%. what is the clearance price?

1 answer:

Maslowich2 years ago

6 0

The clearance price of hat is $17.28

Step-by-step explanation:

Price paid by store = $20

Increment = 60% of price paid

Increment = $\frac{60}{100}*20 = \frac{1200}{100}$

Increment = $12

Increased price = 20+12 = $32

Sale = 10%

Discount amount = 10% of increased price

Discount amount = $\frac{10}{100}*32=\frac{320}{100}$

Discount amount = $3.2

Sale price = 32 - 3.2 = $28.8

Clearance sale = 40%

Discount of clearance sale = 40% of sale price

Discount = $\frac{40}{100}*28.8=\frac{1152}{100}$

Discount = $11.52

Clearance price = sale price - Discount of clearance sale

Clearance price = 28.8 - 11.52 = $17.28

The clearance price of hat is $17.28

Keywords: percentage, subtraction

Learn more about subtraction at:

#LearnwithBrainly

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$2x + 2 = 3x - 52$

$2 + 52 = 3x - 2x$

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4 0

2 years ago

Read 2 more answers

If a ball is thrown straight up into the air with an initial velocity of 70 ft/s, its height in feet after t seconds is given by

Vitek1552 [10]

Answer:

a) Average velocity at 0.1 s is 696 ft/s.

b) Average velocity at 0.01 s is 7536 ft/s.

c) Average velocity at 0.001 s is 75936 ft/s.

Step-by-step explanation:

Given : If a ball is thrown straight up into the air with an initial velocity of 70 ft/s, its height in feet after t seconds is given by $y = 70t-16t^2$ .

To find : The average velocity for the time period beginning when t = 2 and lasting. a. 0.1 s. , b. 0.01 s. , c. 0.001 s.

Solution :

a) The average velocity for the time period beginning when t = 2 and lasting 0.1 s.

$(\text{Average velocity})_{0.1\ s}=\frac{\text{Change in height}}{0.1}$

$(\text{Average velocity})_{0.1\ s}=\frac{h_{2.1}-h_2}{0.1}$

$(\text{Average velocity})_{0.1\ s}=\frac{(70(2.1)-16(2.1)^2)-(70(0.1)-16(0.1)^2)}{0.1}$

$(\text{Average velocity})_{0.1\ s}=\frac{69.6}{0.1}$

$(\text{Average velocity})_{0.1\ s}=696\ ft/s$

b) The average velocity for the time period beginning when t = 2 and lasting 0.01 s.

$(\text{Average velocity})_{0.01\ s}=\frac{\text{Change in height}}{0.01}$

$(\text{Average velocity})_{0.01\ s}=\frac{h_{2.01}-h_2}{0.01}$

$(\text{Average velocity})_{0.01\ s}=\frac{(70(2.01)-16(2.01)^2)-(70(0.01)-16(0.01)^2)}{0.01}$

$(\text{Average velocity})_{0.01\ s}=\frac{75.36}{0.01}$

$(\text{Average velocity})_{0.01\ s}=7536\ ft/s$

c) The average velocity for the time period beginning when t = 2 and lasting 0.001 s.

$(\text{Average velocity})_{0.001\ s}=\frac{\text{Change in height}}{0.001}$

$(\text{Average velocity})_{0.001\ s}=\frac{h_{2.001}-h_2}{0.001}$

$(\text{Average velocity})_{0.001\ s}=\frac{(70(2.001)-16(2.001)^2)-(70(0.001)-16(0.001)^2)}{0.001}$

$(\text{Average velocity})_{0.001\ s}=\frac{75.936}{0.001}$

$(\text{Average velocity})_{0.001\ s}=75936\ ft/s$

5 0

3 years ago

Which number can each term of the equation be multiplied by to eliminate the fractions before solving?

DiKsa [7]

Answer:

12

Hope it helps

4 0

2 years ago

a satellite's escape velocity is 6.5 mi/sec, the radius of the earth is 3960 mi, and the earth's gravitational constant is 32.2

Artyom0805 [142]

Answer:

$23.89x10^{6}$ ft

Step-by-step explanation:

$\frac{V^{2} }{R^{2} } = \frac{2g}{R+h} \\$ This is the formula to find satellite's escape velocity V , where R is earth's radius, h is the satellite's height from the earth surface and g is the earth's gravitational constant.

$R^{2}(R+h) \frac{V^{2} }{R^{2} } =R^{2} (R+h)\frac{2g}{R+h}$ (Multiplying to clear the fractions)

(R+h) $V^{2} =R^{2} 2g$

$R+h=\frac{2R^{2}g }{V^{2} }$

$h= \frac{2R^{2} g}{V^{2} } -R$

Now, we can determine height of satellite from the surface of the earth

by putting the values in above equation

$h= \frac{2 * (3960)^{2}*32.2 }{6.5^{2} } -3960\\h= 23.902 x10^{6} - 3960\\ h=23.89x10^{6} ft$

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2 years ago

A ball is thrown straight up from a height of 3 ft with a speed of 32 ft/s. Its height above the ground after x seconds is given

IceJOKER [234]

Answer:

19ft

Step-by-step explanation:

Given the height of a ball above the ground after x seconds given by the quadratic function y = -16x2 + 32x + 3, we can find the maximum height reached by the ball since we are not told what to look for.

The velocity of the ball is zero at maximum height and it is expressed as:

V(x) = dy/dx

V(x) = -32x+32

Since v(x) = 0

0 = -32x+32

32x = 32

x = 32/32

x = 1s

Get the height y

Recall that y = -16x² + 32x + 3.

Substitute x = 1

y = -16(1)²+32(1)+3

y = -16+32+3

y = -16+35

y = 19ft

Hence the maximum height reached by the ball is 19ft

7 0

2 years ago