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leva [86]
3 years ago
12

Find the length of AD in the diagram shown.

Mathematics
1 answer:
Sophie [7]3 years ago
5 0
No diagram :(
can you upload a picture so we can help out or a description? thanks!
You might be interested in
Select the correct answer.
mariarad [96]

The answer to this Question is A

What is Absolute Value Function or so called Modulus Function or Mod function?

It is a function that takes all real values as input and returns same values but +ve in nature eg if you give input as 2, output will be 2 and if you give input as -2, you will get output 2 again

Solution:

We have expression Ix-5I + 2

we know that I anything I , called as mod of anything, is always greater than or equal to zero so if we take its minimum value as 0 and we get 0 + 2 = 2

means this expression cant be less than 2 hence it will be greater than or equal to 2

because minimum value of mod is 0 and we are adding 2 to it hence overall the expression will be greater than 2 only

To learn more about Absolute Value Function click the link:

brainly.com/question/28478005

#SPJ9

4 0
1 year ago
Which expression is equivalent to
Maksim231197 [3]

Answer:

a

Step-by-step explanation:

3 0
3 years ago
Learning Thoery In a learning theory project, the proportion P of correct responses after n trials can be modeled by p = 0.83/(1
elena-s [515]

Answer:

a)P(n=3) = \frac{0.83}{1+e^{-0.2(3)}}= \frac{0.83}{1+ e^{-0.6}} = 0.536

b) P(n=7) = \frac{0.83}{1+e^{-0.2(7)}}= \frac{0.83}{1+ e^{-1.4}} = 0.666

c) 0.75 =\frac{0.83}{1+e^{-0.2n}}

1+ e^{-0.2n} = \frac{0.83}{0.75}= \frac{83}{75}

e^{-0.2n} = \frac{83}{75}-1= \frac{8}{75}

ln e^{-0.2n} = ln (\frac{8}{75})

-0.2 n = ln(\frac{8}{75})

And then if we solve for t we got:

n = \frac{ln(\frac{8}{75})}{-0.2} = 11.19 trials

d) If we find the limit when n tend to infinity for the function we have this:

lim_{n \to \infty} \frac{0.83}{1+e^{-0.2t}} = 0.83

So then the number of correct responses have a limit and is 0.83 as n increases without bound.

Step-by-step explanation:

For this case we have the following expression for the proportion of correct responses after n trials:

P(n) = \frac{0.83}{1+e^{-0.2t}}

Part a

For this case we just need to replace the value of n=3 in order to see what we got:

P(n=3) = \frac{0.83}{1+e^{-0.2(3)}}= \frac{0.83}{1+ e^{-0.6}} = 0.536

So the number of correct reponses  after 3 trials is approximately 0.536.

Part b

For this case we just need to replace the value of n=7 in order to see what we got:

P(n=7) = \frac{0.83}{1+e^{-0.2(7)}}= \frac{0.83}{1+ e^{-1.4}} = 0.666

So the number of correct responses after 7 weeks is approximately 0.666.

Part c

For this case we want to solve the following equation:

0.75 =\frac{0.83}{1+e^{-0.2n}}

And we can rewrite this expression like this:

1+ e^{-0.2n} = \frac{0.83}{0.75}= \frac{83}{75}

e^{-0.2n} = \frac{83}{75}-1= \frac{8}{75}

Now we can apply natural log on both sides and we got:

ln e^{-0.2n} = ln (\frac{8}{75})

-0.2 n = ln(\frac{8}{75})

And then if we solve for t we got:

n = \frac{ln(\frac{8}{75})}{-0.2} = 11.19 trials

And we can see this on the plot attached.

Part d

If we find the limit when n tend to infinity for the function we have this:

lim_{n \to \infty} \frac{0.83}{1+e^{-0.2t}} = 0.83

So then the number of correct responses have a limit and is 0.83 as n increases without bound.

5 0
3 years ago
Please help ASAP!!!!!
Viefleur [7K]
Use pythagorean’s theorem
as you can see it’s a right isosceles triangle

so your equation is adapted to this:
p^2 + p^2=44^2
add like terms and simplify
2p^2=1936
divide by 2
p^2=968
square root
p= √968
simplify
p=22√2

the answer would be your second option
3 0
3 years ago
Write the expression in complete factored form 2a(x-8) + q(x-8)
Mnenie [13.5K]

Answer:

x-8 out of 2a(x-8)+q(x-8)

Step-by-step explanation:


7 0
3 years ago
Read 2 more answers
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