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ycow [4]
3 years ago
5

1. What does PEMDAS stand for? P: E: M: D: A: S:

Mathematics
2 answers:
Makovka662 [10]3 years ago
5 0

Answer:

Step-by-step explanation:

p=parentheses

e=exponents

m=multiplication

d=division

a=addition

s=subtraction

Zigmanuir [339]3 years ago
3 0

Answer:

P- arenthesis

E- xpontent

M- ultiplication

D- ivision

A- ddition

S- ubtraction

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Each morning John eats some eggs. On any given morning, the number of eggs he eats is equally likelyto 1, 2, 3, 4, or 5 independ
qaws [65]

Answer:

Mean = 3

Variance = 2

Step-by-step explanation:

Since number of eggs he eats is equally likely to any 5 numbers, probability of each one will be (1/5) = 0.2

The probability mass function will therefore be

x 1 2 3 4 5

p 0.2 0.2 0.2 0.2 0.2

The mean is given as the expected value

And expected value is given as

E(X) = Σ xᵢpᵢ

where x = each possible sample space

p = probability of the sample space occurring.

E(X) = (1×0.2) + (2×0.2) + (3×0.2) + (4×0.2) + (5×0.2) = 3 eggs.

b) Variance is given by

Variance = Var(X) = Σx²p − μ²

where μ = E(X)

Σx²p = (1² × 0.2) + (2² × 0.2) + (3² × 0.2) + (4² × 0.2) + (5² × 0.2) = 0.2 + 0.8 + 1.8 + 3.2 + 5 = 11

Var(X) = Σx²p − μ² = 11 - 3² = 11 - 9 = 2

5 0
3 years ago
Two pools are being filled with water. To start, the first pool contains 1900 liters of water and the second pool contains 1529
daser333 [38]

Answer:

after 36 minutes the two pools will have the same amount of water.

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Step-by-step explanation:

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The sample space of a random experiment is {a, b, c, d, e, f}, and each outcome is equally likely. A random variable is defined
Oksi-84 [34.3K]

Answer:

X ____ : 0 ______ 1.4 _____ 2 _____ 3

P(X) ___ 1/3 _____ 1/3 _____ 1/6 ____ 1/6 ;

0 ;

1/2 ;

0 ;

2/3 ;

1/2

Step-by-step explanation:

Each has the same probability ;

X ___ : 0 ___ 0 ___ 1.4 ____1.4 ___ 2 ___ 3

P(x) __ 1/6 __1/6 ___ 1/6 ___ 1/6 ___1/6 __ 1/6

Probability : required outcome / Total possible outcomes

X = 0

P(x = 0) = 1/6 + 1/6 = 2/6 = 1/3

X = 1.4

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Hence ;

X ____ : 0 ______ 1.4 _____ 2 _____ 3

P(X) ___ 1/3 _____ 1/3 _____ 1/6 ____ 1/6

A) P(X = 1.6).B) P(0.5 < X < 2.7).C) P(X > 3).D) P(0 ≤ X < 2).E) P(X = 0 or X = 2).

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P(X = 1.6) = 0

B.)

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C.)

P(X > 3) = 0

D.)

P(0 ≤ X < 2) = P(0) + P(1.4)

P(0) + P(1.4) = 1/3 + 1/3 = 2/3

E.)

P(X = 0 or X = 2) = 1/3 + 1/6 = (2 + 1)/6 = 3/6 = 1/2

4 0
3 years ago
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