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Svetllana [295]
2 years ago
13

If p is true and q is false, what is the truth value of p or q? 1 0 true false

Mathematics
1 answer:
irakobra [83]2 years ago
7 0

Answer:

1 is the answer.............

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Write each statement as an algebraic expression.
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Just go through it phrase by phrase by phrase - one step at a time.

2*(       )
2*(x - 7)
\frac{2*(x - y)}{5*x*y}
6 0
3 years ago
Of 60 corn seeds that were planted, 18 of them did not sprout. What percent of the corn seeds
Lyrx [107]

Answer:

30%

Step-by-step explanation:

18 / 60 = .3 * 100 = 30%

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3 years ago
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Digging a rectangular pool 42ft×29.5×8ft. Hauling truck holds 452.5 cubic feet of dirt. How many truck loads will it take to hau
kiruha [24]

It will take 22 truck loads to haul all the dirt away.

42×29.7×8=9912

9912÷425.5=42 truckloads

6 0
2 years ago
Please see attachment
Dafna11 [192]

Answer:

a) The value of absolute minimum value = - 0.3536  

b) which is attained at   x = \frac{1}{\sqrt{2} }  

Step-by-step explanation:

<u>Step(i)</u>:-

Given function

                       f(x) = \frac{-x}{2x^{2} +1}     ...(i)

Differentiating equation (i) with respective to 'x'

                     f^{l} = \frac{2x^{2} +1(-1) - (-x) (4x)}{(2x^{2}+1)^{2}  }   ...(ii)

                    f^{l}(x) = \frac{2x^{2}-1}{(2x^{2}+1)^{2}  }

Equating Zero

                   f^{l}(x) = \frac{2x^{2}-1}{(2x^{2}+1)^{2}  } = 0

                 \frac{2x^{2}-1}{(2x^{2}+1)^{2}  } = 0

                2 x^{2}-1 = 0

               2 x^{2} = 1

             x^{2}  = \frac{1}{2}

             x = \frac{-1}{\sqrt{2} }  , x = \frac{1}{\sqrt{2} }

<u><em>Step(ii):</em></u>-

Again Differentiating equation (ii) with respective to 'x'

f^{ll}(x) = \frac{(2x^{2} +1)^{2} (4x) - 2(2x^{2} +1) (4x)(2x^{2}-1) }{(2x^{2}+1)^{4}  }

put

      x = \frac{1}{\sqrt{2} }

f^{ll} (x) > 0

The absolute minimum value at   x = \frac{1}{\sqrt{2} }

<u><em>Step(iii):</em></u>-

The value of absolute minimum value

                         f(x) = \frac{-x}{2x^{2} +1}

                       f(\frac{1}{\sqrt{2} } ) = \frac{-\frac{1}{\sqrt{2} } }{2(\frac{1}{\sqrt{2} } )^{2} +1}

         on calculation we get

The value of absolute minimum value = - 0.3536      

<u><em>Final answer</em></u>:-

a) The value of absolute minimum value = - 0.3536  

b) which is attained at   x = \frac{1}{\sqrt{2} }    

3 0
2 years ago
The theater club spends $1,197 for 63 student tickets.
Dmitriy789 [7]

Answer:

19 dollars per student

Step-by-step explanation:

4 0
3 years ago
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