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liraira [26]
4 years ago
7

Tell whether the triangle with the given sides lengths is a right triangle

Mathematics
1 answer:
Andre45 [30]4 years ago
3 0
If this is a right triangle, then a^{2}+ b^{2}= c^{2} where c is the hypotenuse which is ALWAYS THE LONGEST SIDE.  Our longest side is 5, so we will set up Pythagorean's Theorem to see if the addition of the squares of a and b = the square of c: (1.4)^{2} +(4.8) ^{2} =(5)^{2}.  Squaring all of that and adding on the left gives us 25=25.  Because this is true, we have proven the converse of the Pythagorean Theorem here and this is a right triangle.
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The measure of the he angle A is 360°

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A boy borrowed his boat 531 feet out into the ocean. When he looked back he saw the house on a cliff above the beach where he se
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259 ft.

Step-by-step explanation:

A triangle is a polygon with three sides and three angles. Types of triangles are isosceles. scalene, equilateral, acute, obtuse and right angled triangle.

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3 years ago
The ratio of the number of Victor’s tools to the number of Ilya’s tools is 5:2. Victor has 42 more tools than Ilya. How many too
irga5000 [103]

Answer:

Victor gives 28 tools to IIya.

Step-by-step explanation:

Consider the provided information

The ratio of the number of Victor’s tools to the number of Ilya’s tools is 5:2

Let V represents the Victor and I represent llya

Therefore,

\frac{V}{I} = \frac{5}{2}

It is given that Victor has 42 more tools than Ilya.

\frac{V}{I} = \frac{5}{2}=\frac{42+I}{I}

Solve the above equation.

\frac{5}{2}=\frac{42+I}{I}

5I=84+2I

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I=28

Thus, IIya has 28 tools.

Victor has 42 more tools than Ilya. Therefore 42 + 28 = 70.

Victor has 70 tools.

We want to find the number of tools victor needs to give to IIya so that the ratio of the number of Victor's tools to the number of Ilya’s tools will be 3:4

Let Victor gives x tools to IIya. Thus,

\frac{3}{4}=\frac{70-x}{28+x}

3(28+x)=4(70-x)

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Hence, Victor gives 28 tools to IIya.

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Solve this it attached
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\\ \sf\longmapsto \dfrac{15}{k}

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Put the value

\\ \sf\longmapsto \dfrac{15}{3}

\\ \sf\longmapsto 5

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