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3 years ago

How do you write 210% as a decimal?

Mathematics

2 answers:

mixas84 [53]3 years ago

5 0

Answer:

I believe it is 2.1 if I am wrong, very sorry.

Step-by-step explanation:

So you divide 200 by 100 so 210/100, thats when you get 2.1. So to convert that from percent to decimal all you do is is just divide by 100 and remove the % sign! Just move the decimal point 2 places to the left. If the percent value is a integer, the '.' is at the right of the right most digit.

Hope this helped you out and hope you got your answer right! Enjoy the rest of your day. :)

pishuonlain [190]3 years ago

3 0

Answer:

2.1

Step-by-step explanation:

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Step-by-step explanation:

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3 years ago

H(t)=2t-2 <br> g(t)=t-1 <br> find h(g(2))

Crazy boy [7]

T = 2

To find this, follow these steps.

First, you need to find g(2):

t-1
2-1
1

Therefore 1 is your first answer. Then you input that answer into h(t).

2(t) - 2
2(2) - 2
4 - 2
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Thus, 2 is your final answer.

Hope this helps!

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3 years ago

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Grace [21]

Answer:

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Step-by-step explanation:

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7 0

3 years ago

Read 2 more answers

Solve the system of equations algebraically: x^2 +y^2 =25, y=x^2 +3

aalyn [17]

Answer:

${ \tt{ {x}^{2} + {y}^{2} = 25 - - - \{eqn(a) \}}} \\ { \tt{y = {x}^{2} + 3 - - - \{eqn(b) \} }}$

» substitute y in eqn(a) with y in eqn(b)

${ \tt{ {x}^{2} + ( {x}^{2} + 3) {}^{2} = 25}} \\ { \tt{ {x}^{2} + ( {x}^{2} + 6x + 9) = 25}} \\ { \tt{2 {x}^{2} + 6x + 9 = 25 }} \\ { \tt{2 {x}^{2} + 6x - 16 = 0}} \\ { \tt{x = 1.7 \: \: and \: \: - 4.7}}$

» Find y in eqn(b)

${ \tt{y = {x}^{2} + 3 }} \\ { \tt{y = 5.89 \: \: and \: \: 25.09}}$

8 0

3 years ago

What is dh/dx if h(x) = cπ, where c is a constant? Please show work. Will mark the best answer as brainliest.

Svetllana [295]

Answer:

$h'(x)=0$

Step-by-step explanation:

By definition, the derivative of $f(x)$ is given by:

$\displaystyle \frac{dy}{dx}=f'(x)=\lim_{h\rightarrow 0}\frac{f(x+h)-f(x)}{h}$

Given $h(x)=c\pi$ , $h(x+4)$ must also be $c\pi$ . Therefore, we have:

$\displaystyle h'(x)=\lim_{h\rightarrow 0}\frac{c\pi - c\pi }{h},\\h'(x)=\lim_{h\rightarrow 0}\frac{0}{h}=\boxed{0}$

Note that the derivative of a constant is always zero since for $f(x)=c$ , where $c$ is some constant, $f(x)=f(x+h)$ and we obtain $c-c$ in the numerator, yielding a final answer of zero.

4 0

3 years ago