Answer:
4a^2-6b^2+12
Step-by-step explanation:
(a^2 - 2b^2 + 3) - (4b^2 - 5) + (3a^2 + 4)
distribute the negative sign to each term in the 2nd expression
a^2-2b^2+3-4b^2+5+3a^2+4
combine like terms
4a^2-6b^2+12
Polygon FGHIJ is the result of the rotation of ABCDE.
A = F ⇒ 117°
B = G ⇒ 90°
C = H ⇒ 127°
D = I ⇒ 90°
E = J ⇒ 117°
The measure of angle BCD remains the same because the rotation involves the whole polygon. Thus, it is still 127°
Answer:

Step-by-step explanation:
Given:
The original function is given as:

The above function is stretched vertically by a factor of 2 to form the graph of
.
According to the rule of function transformations, when the graph of a function is stretched in the vertical direction by a factor of 'C', where, 'C' is a number greater than 1, then the function rule is given as:

Therefore, the function is multiplied by a factor of 'C' to get the equation of the stretched function.
Here, the the value of 'C' is 2. So, the equation of
is given as:
![g(x)=2f(x)\\g(x)=2[2(3)^{x+1}+4]\\g(x)=4(3)^{x+1}+8](https://tex.z-dn.net/?f=g%28x%29%3D2f%28x%29%5C%5Cg%28x%29%3D2%5B2%283%29%5E%7Bx%2B1%7D%2B4%5D%5C%5Cg%28x%29%3D4%283%29%5E%7Bx%2B1%7D%2B8)
Therefore, the equation of
is
.
Yes because the results are unlikely to occur by chance, is what I think .
Answer:
You would need 6 1/4 cups of sugar.