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LuckyWell [14K]
4 years ago
11

2. Yunika downloaded four applications for $2.99 each to her cell phone. The remaining applications that Yunika purchased cost $

1.99 each.If she downloaded x total applications, which of the following equations can be used to find how much Yunika spent on cell phone application downloads? 10 points A. y = 1.99(x - 4) + 11.96 B. y = 11.96(x - 4) + 1.99 C. y = 1.99x + 11.96 D. y = 11.96x + 1.99
Mathematics
2 answers:
Gelneren [198K]4 years ago
4 0

Answer:

The answer is A. y = 1.99(x - 4) + 11.96

Step-by-step explanation:

The answer is correct because someone i know has taken the quiz and got it right.

GenaCL600 [577]4 years ago
3 0
Jajajajsisoododeiwksjiais
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Driving under the influence of alcohol (DUI) is a serious offense. The following data give the ages of a random sample of 50 dri
o-na [289]

Answer:

Explanation below.

Step-by-step explanation:

For this case we have the following dataset:

46, 16, 41, 26, 22 ,33, 30, 22 ,36, 34,

63, 21, 26, 18, 27, 24, 31, 38, 26, 55,

31,  47, 27, 43 ,35, 22 ,64,40, 58, 20,

49, 37, 53, 25, 29, 32, 23, 49, 39, 40,

24, 56, 30, 51, 21, 45, 27, 34, 47, 35

So we have 50 values. The first step on this case would be order the dataset on increasing way and we got:

16, 18, 20, 21, 21, 22, 22, 22, 23, 24,

24, 25, 26, 26, 26, 27, 27, 27, 29, 30

30, 31, 31, 32, 33, 34, 34, 35, 35, 36,

37, 38, 39, 40, 40, 41, 43, 45, 46, 47,

47, 49, 49, 51, 53, 55, 56, 58, 63, 64

We can find the range for this dataset like this:

Range = Max-Min = 64-16 =48

Then since we need 7 classes we can find the length for each class doing this:

W = \frac{48}{7}=6.86

And now we can define the classes like this and counting how many observations lies on each interval we got the frequency:

  Class           Frequency      Midpoint           RF                   CF

________________________________________________

[16-22.86)              8               19.43         (8/50)=0.16           0.16

[22.86-29.71)         11              26.29        (11/50)=0.22          0.38

[29.71-36.57)         11               33.14         (11/50)=0.22          0.6

[36.57-43.43)         7               40.0          (7/50)=0.14           0.74

[43.43-50.29)        6               46.86        (6/50)=0.12          0.86

[50.29-57.14)         4               53.72        (4/50)=0.08         0.94

[57.14-64]               3               60.57        (3/50)=0.06           1.0

________________________________________________

Total                         50                                         1.00

RF= Relative frequency. CF= Cumulative frequency

The relative frequency was calculated as the individual frequency for a class divided by the total of observations (50)

The mid point is the average between the limits of the class.

And the cumulative frequency is calculated adding the relative frequencies for each class.

8 0
4 years ago
Someone help me with math problems ASAP!!!!!
Nonamiya [84]

Answer:

9 1/3

Step-by-step explanation:

4 0
4 years ago
Read 2 more answers
Can someone please help me with this, I need to show work for it too.
Anastaziya [24]

Answer:

Step-by-step explanation:

Muy difícil pa

3 0
3 years ago
An object is thrown upward from the top of an 80ft tower.
sweet [91]
C because if you solve for the solutions for the quadratic, then you get 5 and -1 but you cant have negative seconds so 5 is the right answer!
5 0
3 years ago
Naomi's fish is 40 millimeters long. Her guinea pig is 25 centimeters long.
timofeeve [1]

Explanation 1:

Her guinea pig is

25 cm  long.

25 cm = 250 mm

Her fish is  40 mm long, so her guinea pig is longer than her fish by

25 cm − 40 mm = 250 mm − 40 mm = 210 mm= 21 cm

Explanation 2:

First, lets convert the length of Naomi's guinea pig from cm to mm.

1 cm=10 mm

We can multiply each side of the equation by 25 to obtain the length of the guinea pig in mm.

25 × 1 cm = 25 ×  10 mm

25 cm = 250 mm

Because we have a length of the guinea pig and the fish in a common metric we can subtract the two values: 250 mm − 40 mm = 210 mm The guinea pig is 210 millimeters longer than the fish. Or, if we want to convert this to centimeters we can divide by 10: 210 millimeters 10 = 21 centimeters

Hope this helps have a good day/night!

4 0
3 years ago
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