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pochemuha
3 years ago
8

Choose the equation that represents the line that passes through the point (-1, 6) and has a slope of -3.

Mathematics
1 answer:
nadya68 [22]3 years ago
5 0

Option 1: y = -3x+3 is the right answer

Step-by-step explanation:

The slope-intercept form is given by:

y = mx+b

Here m is the slope and b is y-intercept

Given

m = -3

Point = (-1,6)

Putting the value of slope

y = -3x+b

To find the value of b, putting the given point (-1,6) in the equation

6 = -3(-1) +b\\6 = 3 + b\\b = 6-3\\b = 3

Putting the value of b in slope-intercept form

y = -3x+3

Hence,

Option 1: y = -3x+3 is the right answer

Keywords: Equation of line, slope

Learn more about equation of line at:

  • brainly.com/question/563623
  • brainly.com/question/558692

#LearnwithBrainly

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Select the correct answer. What is the mode of this data set? {41, 43, 45, 3, 11, 23, 24, 27, 29, 45, 12, 19, 22, 49, 25}
klemol [59]

The mode is the number in the set that appears the most.


In the given data set, the number 45 is listed twice while all the other numbers are only listed once.

The mode is 45.


4 0
3 years ago
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Write an equation for this relationship.
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Answer:

y=18.5x

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74-55.5=18.50

92.50-74=18.50

111-92.5=18.50

(3,55.50)

y=18.5x +b

55.50=18.5(3)+b

55.50=55.50+b

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8 0
3 years ago
Tickets to a concert cost $70, or $20 with a student discount. Ticket sales must exceed $500,000 for the group to perform. If 20
Angelina_Jolie [31]

Solution:

Let x = the number of $70 seats sold

Let y = the number of $20 seats sold

x+y ≤ 20,000

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4 0
3 years ago
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Which coefficient matrix represents a system of linear equations that has a unique solution ?
finlep [7]

Answer:

Option C

Step-by-step explanation:

We are given a coefficient matrix along and not the solution matrix

Since solution matrix is not given we cannot check for infinity solutions.

But we can check whether coefficient matrix is 0 or not

If coefficient matrix is zero, the system is inconsistent and hence no solution.

Option A)

|A|=\left[\begin{array}{ccc}4&2&6\\2&1&3\\-2&3&-4\end{array}\right] =0

since II row is a multiple of I row

Hence no solution or infinite

OPtion B

|B|=\left[\begin{array}{ccc}2&0&-2\\-7&1&5\\4&-2&0\end{array}\right] \\=2(10)-2(10)=0

Hence no solution or infinite

Option C

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Hence there will be a unique solution

Option D

\left[\begin{array}{ccc}5&10&5\\4&1&4\\-1&-2&-1\end{array}\right] \\=2(10)-2(10)=0=0

(since I row is -5 times III row)

Hence there will be no or infinite solution

Option C is the correct answer



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