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Nat2105 [25]
3 years ago
9

7^2+3(4^2+3+2) what does this mean please help and fast!!!!

Mathematics
2 answers:
MAVERICK [17]3 years ago
7 0

Answer:

112

Step-by-step explanation:

The arrow means multiplying but really you need to Pemdas

wlad13 [49]3 years ago
4 0

Answer:

112

Step-by-step explanation:

Using PEMDAS

1) (4^2+3+2)

= 16 + 3 + 2

= 21

2) 7^2 + 3 * 21

= 49 + 3 * 21

= 49 + 63

= 112

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(1 point) Suppose we want a 95% confidence interval for the average amount spent on books by freshmen in their first year at col
Ne4ueva [31]

Answer:

a) n=(\frac{1.960(16)}{5})^2 =39.33 \approx 40

So the answer for this case would be n=40 rounded up to the nearest integer

b) For this case if we see the formula for the margin of error

ME=z_{\alpha/2}\frac{s}{\sqrt{n}}    (a)

We can see that the margin of error is inversely proportional to the sample size so if we want a samller margin of error we need a LARGER sample

Answer: LARGER

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean

\sigma=16 represent the population standard deviation

n represent the sample size  

Solution to the problem

Part a

The margin of error is given by this formula:

ME=z_{\alpha/2}\frac{s}{\sqrt{n}}    (a)

And on this case we have that ME =5 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2   (b)

The critical value for 95% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.025;0;1)", and we got z_{\alpha/2}=1.960, replacing into formula (b) we got:

n=(\frac{1.960(16)}{5})^2 =39.33 \approx 40

So the answer for this case would be n=40 rounded up to the nearest integer

Part b

For this case if we see the formula for the margin of error

ME=z_{\alpha/2}\frac{s}{\sqrt{n}}    (a)

We can see that the margin of error is inversely proportional to the sample size so if we want a samller margin of error we need a LARGER sample

Answer: LARGER

5 0
3 years ago
PLZ help I will mark as brainliest
Elden [556K]

Answer:

  6750 - 3894 = 2856

Step-by-step explanation:

You have to make use of the arithmetic facts you know.

The least-significant asterisk must be 0, because the sum of 4 and 6 is 10.

The 10s asterisk must be 9,so that the sum 5 + 9 + 1 has a least-significant digit of 5.

The 100s asterisk must be 7, because that is the least-significant digit of the sum 8 + 8 + 1 = 17.

The 1000s asterisk must be 3, so that 2 + 3 + 1 = 6.

(The "1" in each of these sums is the carry from the sum of the digits with the next lower place value.)

So, the subtraction problem is ...

  6750 - 3894 = 2856

_____

<em>Comment on the solution method</em>

For the most part, we worked this as an addition problem. The sum of the last two numbers must be equal to the first: 6570 = 3894 +2856. For some of us, addition facts are easier to work with than subtraction facts. The carry/borrow can be less confusing that way.

6 0
3 years ago
Show that det(A) = 0 without directly evaluating the determinant. A = [-4 1 1 1 1; 1 -4 1 1 1; 1 1 -4 1 1; 1 1 1 -4 1; 1 1 1 1 -
Anuta_ua [19.1K]
You could interpret them as system of equation and answer the question easily

from A 

-4x + y + x + w =1

write in same form from A 

as this system has five variables and four of them are unknowns it means the unique solution is not possible 

So, det (A) = 0



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3 years ago
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Answer: 160 times

Step-by-step explanation:

7 0
4 years ago
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You blindfold your friend. You give him a bowl that contains 10 silver marbles and 6 black marbles. What is the minimum number o
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Answer:

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Step-by-step explanation:

Since your friend is blindfolded the only actual way for him to be completely sure that they picked out all 6 black marbles would be to pick out all of the marbles until none are left. As long as there is even one marble in the bag then your friend will still not be sure which color it is due to being blindfolded. Therefore, under these circumstances the answer would be 16 marbles.

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