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leonid [27]
3 years ago
15

37th term; a1 = 2.3; d = -2.3

Mathematics
1 answer:
Sindrei [870]3 years ago
7 0

<u>Answer:</u>

37th term of given arithmetic sequence a_1 = 2.3; d = -2.3 is -80.5.

<u>Solution:</u>

Given that  

Need to determine 37th term, when a_1 = 2.3, d = -2.3

Means first term of arithmetic sequence = a_1 = 2.3 and common difference d = -2.3

<u><em>Formula for nth term of arithmetic sequence is  </em></u>

\mathrm{a}_{\mathrm{n}}=\mathrm{a}_{1}+(\mathrm{n}-1) \mathrm{d}  --- equation 1

\text { In our case } a_{1}=2.3, d=-2.3

We need to determine 37th term so n = 37.

On substituting given values in equation (1) we get

\mathrm{a}_{37}=\mathrm{a}_{1}+(37-1) \mathrm{d}

\begin{array}{l}{\Rightarrow a_{37}=2.3+(37-1)(-2.3)} \\\\ {\Rightarrow a_{37}=2.3(1-36)=2.3 \times 35=-80.5}\end{array}

Hence 37th term of given arithmetic sequence is -80.5

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Answer:

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Step-by-step explanation:

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therefore the correct options are:

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3 years ago
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Ymorist [56]
I'll do a and e on the first one to show you how to do it

Then See if you can do the rest

a. 6(-3)<span><span>
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</span>Now for the second question <span>

</span>I will do a and d to show you how to do this then you do the rest<span> (I'm inserting a picture with these)

</span>a. 4(-2 \frac{1}{3}) + 7 \frac{1}{6}
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