Answer:
Step-by-step explanation:
We have to simplify the original function using partial fraction, hence:
![From\ Laplace\ inverse:\\\\But\ L^{-1}[\frac{1}{s-a} ]=e^{at}\\\\Hence:\\\\L^{-1} [\frac{5s}{s^2+3s-4}]=L^{-1}[\frac{1}{s-1} ]+L^{-1}[\frac{4}{s+4} ]=e^{t}+4e^{-4t}\\\\L^{-1} [\frac{5s}{s^2+3s-4}]=e^{t}+4e^{-4t}](https://tex.z-dn.net/?f=From%5C%20Laplace%5C%20inverse%3A%5C%5C%5C%5CBut%5C%20L%5E%7B-1%7D%5B%5Cfrac%7B1%7D%7Bs-a%7D%20%5D%3De%5E%7Bat%7D%5C%5C%5C%5CHence%3A%5C%5C%5C%5CL%5E%7B-1%7D%20%5B%5Cfrac%7B5s%7D%7Bs%5E2%2B3s-4%7D%5D%3DL%5E%7B-1%7D%5B%5Cfrac%7B1%7D%7Bs-1%7D%20%5D%2BL%5E%7B-1%7D%5B%5Cfrac%7B4%7D%7Bs%2B4%7D%20%5D%3De%5E%7Bt%7D%2B4e%5E%7B-4t%7D%5C%5C%5C%5CL%5E%7B-1%7D%20%5B%5Cfrac%7B5s%7D%7Bs%5E2%2B3s-4%7D%5D%3De%5E%7Bt%7D%2B4e%5E%7B-4t%7D)
Multiplying both sides of a rational equation by a variable expression introduces the possibility of extraneous solutions. Therefore, we must check the solutions against the set of restrictions. If a solution is a restriction, then it is not part of the domain and is extraneous.
Answer:
one solution and x=40
Step-by-step explanation:
8x-32=6x+48
2x=80
80÷2
x=40
Answer:
53.2 kg
Step-by-step explanation:
Let E represent Esther's weight. Then Henry's weight is E/2, and David's weight is E-5.2. Their average weight is ...
((E-5.2) + E + (E/2))/3 = 42.6
2.5E -5.2 = 127.8 . . . . . . . . . . multiply by 3, simplify
2.5E = 133 . . . . . . . . . . . . . . . . add 5.2
E = 133/2.5 = 53.2 . . . . kg
Esther's weight is 53.2 kg.
Answer:
.375
Step-by-step explanation:
