Question

Is the relationship linear, exponential, or neither?

Answer 1

Answer:

Neither linear nor exponential

Step-by-step explanation:

To check for a linear relationship.  Find slope.

slope=  (-1  -  (-2)) / ( 5 - 2)  = 1/3

check  other points

slope = (1 - (-1) )/ (8 - 5) =  2/3

check more

slope = (4 - 1) / (11 - 8) = 3/ 3 = 1

Nope.

try assuming an exponential:

y = c * (a^x)

-2 =  c* (a^2);    -2/c = a^2

-1 = c *(a ^5);    -1/c = a^5

1 =  c * (a^8),     1/c = a^8

(-2/c)^4 = a^8 = 1/c

16/(c^4) = 1/c

c^3 = 16,  then    a = root (-2/ cube-root(16) )

The change from negative to postive  would not work  for y = c(a^x)

so...

assume   y =  a^x  + k

-2 = a^2  + k

-1 = a^5  + k

...  I would say neither..