Solve for x -3x+6=2x-24-30-6 630

Mathematics

1 answer:

Svetach [21]4 years ago

8 0

-3x + 6 = 2x - 24.

Add 3x to both sides.

6 = 5x - 24.

Add 24 to both sides.

30 = 5x.

Divide it all by 5.

x = 6.

You might be interested in

Find g: 3g + 15 − 12 + 3 − 2g + 4 = 1

lisov135 [29]

Answer:Group of answer choices

Step-by-step explanation:

What you first want to do is like and unlike terms so basically liketerms are terms withthe same sign and unlike terms are terms with diferent signs for instinse 3g and 2g are like terms so -33 and -9 and -9 and 9 are unlike terms so you just have to find the like and unlike terms to answer the question!

6 0

3 years ago

Read 2 more answers

4 1/3pt = how many cups

Zina [86]

4 1/3pt = how many cups
=17

6 0

3 years ago

I need help plz. Its DeMoivres Theorem

vagabundo [1.1K]

$\bf \qquad \textit{power of two complex numbers} \\\\\ [\quad r[cos(\theta)+isin(\theta)]\quad ]^n\implies r^n[cos(n\cdot \theta)+isin(n\cdot \theta)] \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ z=\stackrel{a}{-1}\stackrel{b}{-\sqrt{3}~i}~~ \begin{cases} r=\sqrt{a^2+b^2}\\ \theta =tan^{-1}\left( \frac{b}{a} \right)\\[-0.5em] \hrulefill\\ r=\sqrt{(-1)^2+(\sqrt{3})^2}\\ \qquad \sqrt{4}\\ \qquad 2\\ \theta =tan^{-1}\left( \frac{-\sqrt{3}}{-1} \right)\\\\ \qquad \frac{4\pi }{3} \end{cases}$

$\bf z=2\left[ cos\left( \frac{4\pi }{3} \right) -i~sin\left( \frac{4\pi }{3} \right)\right]\implies z^6=\left[ 2\left[ cos\left( \frac{4\pi }{3} \right) -i~sin\left( \frac{4\pi }{3} \right)\right] \right]^6 \\\\\\ z^6=2^6\left[ cos\left( 6\cdot \frac{4\pi }{3} \right) -i~sin\left( 6\cdot \frac{4\pi }{3} \right)\right]\implies z^6=64[cos(8\pi )-i~sin(8\pi )] \\\\\\ z^6=64[(-1)-i~(0)]\implies z^6=\stackrel{\stackrel{a}{\downarrow }}{-64}~~\stackrel{\stackrel{b}{\downarrow }}{-0i}$