A sequence of numbers consists of natural numbers that are
1 answer:
Given :
A sequence of numbers consists of natural numbers that are
not perfect squares.
To Find :
The 1000th member of this sequence .
Solution :
Now , and
.
So , there are 31 numbers before 1000 which are perfect square .
Therefore , the is 1000+31 = 1031 .
Also , the first perfect square after 1000 is 32 .
So , we have to continue to 1031 + 1 = 1032 to compensate for the 32nd square.
Therefore , the 1000th member of this sequence is 1032 .
Hence , this is the required solution .
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