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Free_Kalibri [48]
3 years ago
6

Show the working pls :))

Mathematics
1 answer:
NemiM [27]3 years ago
3 0

Answer:

$ 78.68

Step-by-step explanation:

The following data were obtained from the question:

Pay >>>>>>>>>> Frequency

40 – 59 >>>>>> 15

60 – 79 >>>>>> 58

80 – 99 >>>>>> 27

100 – 119 >>>>> 22

Mean pay =?

Next, we shall determine the class pay. This can be obtained by adding the pay together and dividing by 2 as shown below:

L => is the lower pay interval

U => is the upper pay interval

Pay >>>>>>>>>> Class pay [(L+U)/2)]

40 – 59 >>>>>> 49.5

60 – 79 >>>>>> 69.5

80 – 99 >>>>>> 89.5

100 – 119 >>>>> 109.5

Thus, the table becomes

Pay >>>>>> Class pay >> Frequency

40 – 59 >> 49.5 >>>>>>> 15

60 – 79 >> 69.5 >>>>>>> 58

80 – 99 >> 89.5 >>>>>>> 27

100 – 119 > 109.5 >>>>>> 22

The mean pay can be obtained as follow:

Summation of class pay and frequency (ΣCF) = (49.5×15) + (69.5×58) + (89.5×27) + (109.5×22)

= 742.5 + 4031 + 2416.5 + 2409

= 9599

Summation of frequency (ΣF) = 15 + 58 + 27 + 22

= 122

Mean pay = ΣCF / ΣF

ΣCF = 9599

ΣF = 122

Mean pay = 9599 / 122

Mean pay = $ 78.68

Therefore, the mean pay is $ 78.68

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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4 {}^{3} .(100 \div 25) - 5 {}^{0}

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