4 pairs of parallel lines
Part A
4 < 5 < 9 is given to us. Apply the square root to each term to end up with this inequality: sqrt(4) < sqrt(5) < sqrt(9)
So sqrt(5) is between <u>sqrt(4)</u> and <u>sqrt(9)</u>
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Part B
Simplify those two mentioned square roots
sqrt(4) = sqrt(2^2) = 2
sqrt(9) = sqrt(3^2) = 3
Therefore, sqrt(5) is also between <u>2</u> and <u>3</u>
We can see this through using a calculator: sqrt(5) = 2.23607 approximately
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Part C
We can now say:
2 < sqrt(5) < 3
Multiply all three sides by 6
6*2 < 6*sqrt(5) < 6*3
So the expression 6*sqrt(5) is between <u>6 x 2</u> and <u>6 x 3</u>
Sure enough, a calculator confirms this
6*sqrt(5) = 13.416408
since 6*2 = 12 and 6*3 = 18. We see that 13.416 is between 12 and 18.
Answer:
1
Step-by-step explanation:
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For the transformation
the Jacobian is
with determinant
The vertices of the triangle in the -plane are
Then the integral is
Answer: -121
Step-by-step explanation: