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3 years ago

How mini groups did he make? How many were in each group

Mathematics

1 answer:

frosja888 [35]3 years ago

4 0

5 students each group...lel

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What is the midpoint of AC ?

Leno4ka [110]

Answer:

A: (m + p, n + r)

Step-by-step explanation:

$Midpoint \: of \: AC \\ = \bigg( \frac{2m + 2p}{2} \: \: \frac{2n + 2r}{2} \bigg) \\ \\ = \bigg( m + p, \: \: n + r \bigg)$

5 0

3 years ago

Using the Law of sines, in triangle ABC, if measurement of angle B = 105°, b = 23, a = 14, find measurement of angle A

Degger [83]

Check the picture below.

make sure your calculator is in Degree mode.

3 0

3 years ago

Vertex and axis of symmetry

Furkat [3]

Answer:

Vertex = (-3, -1)

Axis of Symmetry: x = -3

Step-by-step explanation:

The vertex is (-3, -1), the axis of symmetry is x = -3. The x-intercept is -2 and -4, the y intercept is 8, the domain is R, the range is [-1, inf.]

The function is increasing in {-3, inf.} and decreasing in {-inf., 3}

5 0

3 years ago

How to solve the inequality 1/5 ≤ x/15?

MAXImum [283]

Answer:

3 <_ x

Step-by-step explanation:

multiply both sides by 15

1/5 * 15 <_ x

15/5 <_ x

3 <_ x

8 0

3 years ago

Given points A (1, 2/3), B (x, -4/5), and C (-1/2, 4) determine the value of x such that all three points are collinear

AlladinOne [14]

Answer:

$x=\frac{83}{50}$

Step-by-step explanation:

we know that

If the three points are collinear

then

$m_A_B=m_A_C$

we have

A (1, 2/3), B (x, -4/5), and C (-1/2, 4)

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

step 1

Find the slope AB

we have

$A(1,\frac{2}{3}),B(x,-\frac{4}{5})$

substitute in the formula

$m_A_B=\frac{-\frac{4}{5}-\frac{2}{3}}{x-1}$

$m_A_B=\frac{\frac{-12-10}{15}}{x-1}$

$m_A_B=-\frac{22}{15(x-1)}$

step 2

Find the slope AC

we have

$A(1,\frac{2}{3}),C(-\frac{1}{2},4)$

substitute in the formula

$m_A_C=\frac{4-\frac{2}{3}}{-\frac{1}{2}-1}$

$m_A_C=\frac{\frac{10}{3}}{-\frac{3}{2}}$

$m_A_C=-\frac{20}{9}$

step 3

Equate the slopes

$m_A_B=m_A_C$

$-\frac{22}{15(x-1)}=-\frac{20}{9}$

solve for x

$15(x-1)20=22(9)$

$300x-300=198$

$300x=198+300$

$300x=498$

$x=\frac{498}{300}$

simplify

$x=\frac{83}{50}$

8 0

3 years ago