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2 years ago

Which equation describes a line parallel to y= 4x+ 5 through point (-2, 1)?

Mathematics

1 answer:

Tema [17]2 years ago

8 0

Hi there!

For a line to be PARALLEL, it must contain the same slope.

The given line has a slope of 4, so we can use the point-slope formula to solve:

$\large\boxed{y - y_1 = m(x - x_1)}$

y1 = y-coordinate of given point

x1 = x-coordinate of given point

m = slope

Plug in the values:

$y - 1 = 4(x - (-2))\\\\y - 1 = 4(x + 2)$

Simplify:

$y - 1 = 4x + 8\\\\\boxed{y = 4x + 9}$

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3 years ago

10x +7 = -3х – 3 help guys

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x = -10/13

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3 years ago

Find the first, fourth, and tenth terms of the arithmetic sequence described by the given rule.

lubasha [3.4K]

Answer:

The answer is option C.

Step-by-step explanation:

The arithmetic sequence is given by

$A(n) = - 6 + (n - 1)( \frac{1}{5} )$

where n is the number of terms

For the first term

n = 1

So we have

$A(1) = - 6 + (1 - 1)( \frac{1}{5} )$

$= - 6 + (0)( \frac{1}{5} )$

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For the fourth term

n = 4

$A(4) = - 6 + (4 - 1)( \frac{1}{5} )$

$= - 6 + (3)( \frac{1}{5} )$

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For the tenth term

n = 10

$A(10) = - 6 + (10 - 1)( \frac{1}{5} )$

$= - 6 + (9)( \frac{1}{5} )$

$= - 4 \frac{1}{5}$

Hope this helps you

4 0

3 years ago