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3 years ago

6

Which equation correctly shows how to determine the distance between the points (9, –2) and (6, 3) on a coordinate grid?

1 answer:

dybincka [34]3 years ago

3 0

Hint: $\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ 9}}\quad ,&{{ -2}})\quad 
% (c,d)
&({{ 6}}\quad ,&{{ 3}})
\end{array}\qquad 
% distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}$

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.. through the points (4,7) and (-6, -6) and put into slope-intercept form

TiliK225 [7]

Answer: y = 1.3x + 1.8

Step-by-step explanation: I used Desmos

5 0

3 years ago

Solve for each unknown

ehidna [41]

<span>6=2+u then u = 6 - 2 = 4
(-16)=(-9)-w then w = 16 - 9 = 7
8=r+4 then r = 8 - 4 = 4
v+(-3)=(-10) then v = -10 + 3 = -7
9=j+7 then j = 9-7 = 2
(-14)=r-6 then r = -14 +6 = -8
(-2)-k=4 then k = -2 -4 = -6
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(-9)=s+(-4) then s = -9 + 4 = -5
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3 years ago

Simplify the cube root in simplest radical form.<br> 9x374<br> Please help

algol [13]

Answer:

D. $xy\sqrt[3]{9y}$

Step-by-step explanation:

$\sqrt[3]{9x^3y^4}$

$\sqrt[3]{9}\sqrt[3]{x^3}\sqrt[3]{y^4}$

The $\sqrt[3]{x^3}$ cancels out to become x:

$\sqrt[3]{9}x\sqrt[3]{y^4}$

Split the $y^4=y*y^3$

$\sqrt[3]{9}x\sqrt[3]{y^3}\sqrt[3]{y^1}$

$\sqrt[3]{y^3} =y$

$xy\sqrt[3]{9} \sqrt[3]{y}$

Put the cube root of y and cube root of 9 together:

$xy\sqrt[3]{9y}$

6 0

3 years ago

QUICK I NEED HELP!!!

Tems11 [23]

Answer:

168

Step-by-step explanation:

photos are enlarged by a certain factor, divide the new width by the old width and youll get the factor (12).

You can then multiply the original height by 12 to get the answer

12 X 14 =168

8 0

2 years ago

Read 2 more answers

Your subtotal at the store was $72.29. You have a 40% off coupon. If the sales tax rate is 9.5%, what is the total price for you

ale4655 [162]

$47.50

Step-by-step explanation:

Before tax proce is $72.29

sales tax is 9.5%= $6.87

$72.29+$6.87=$79.16

40% off of $79.16=$47.50

8 0

3 years ago