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cestrela7 [59]
3 years ago
15

Find the area of the triangle with the given measurements. Round the solution to the nearest hundredth if necessary. B = 71°, a

= 11 cm, c = 18 cm
Mathematics
2 answers:
mr_godi [17]3 years ago
6 0
\boxed{\text{Area of the triangle:}  \dfrac{a \times c \times sin(\measuredangle B)}{2}}  \\  \\  A =  \dfrac{a \times c \times sin(\measuredangle B)}{2}  \\  \\  A= \dfrac{11 \times 18 \times sin71 ^o }{2}   \\  \\  \\  Note : sin 71^o \approx 0,94 \\  \\  \\  A =  \dfrac{198 \times 0,94}{2}  \\  \\  A= \dfrac{186.12}{2} \\  \\ A=93.6 \ cm^2
Pepsi [2]3 years ago
6 0

Answer:

93.606 cm^2

Step-by-step explanation:

Given that in a triangle two sides are 11 and 18 cm and included angle is 71 degrees

a=11\\c=18\\angleB =71

We know that area of a triangle when two sides and included angle is known is given by

Area of a triangle = \frac{1}{2} ac sin B\\=\frac{1}{2} (11)(18)sin 71\\= 99 (0.9455)\\\\=-93.603 cm^2

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