All categories

1 year ago

What is 4/5 = 12/blank | Equivalent Fractions

Mathematics

2 answers:

harina [27]1 year ago

6 0

Answer:

Step-by-step explanation:

4/5 = 12/blank.

well 12/4 is 3

3 * 5 is 15.

the blank is 15

slava [35]1 year ago

6 0

Answer:

12/15

Step-by-step explanation:

4/5x3/3=12/15

since 12 is 3 times greater than 4, you must multiply both the numerator and the denominator by 3.

You might be interested in

A gift box is in the shape of a trapezoidal prism with the base lengths of 7 inches and 5 inches and a height of 4 inches. The h

ale4655 [162]

384 in^{3}. because if you have to add the bases together then so 7+5=12 then you times the width and height together so 4*8=32. Then you times 12 * 32 = 384.

HOPED THIS
HELPED!!!!!!!!!

7 0

3 years ago

dangina [55]

Answer:

im not reading all of that

Step-by-step explanation:

6 0

2 years ago

3. Write an equation of a line that is perpendicular to the line x – 2y = 8.

xenn [34]

Answer:

y=0.5x+40

Step-by-step explanation:

Copy the equation.

x-2y=8

Subtract x from both sides.

-2y=-x-8

Divide both sides by -2.

y=0.5x+4

Now we know the slope is 0.5.

Any line with a slope of 0.5 will be perpendiculr to the original line.

One that you can use is y=0.5x+40.

7 0

2 years ago

The probability than an event happens is .42. what is the probability that the event won't happen

Fed [463]

The probability that the event won't happen would be .58.

3 0

2 years ago

Find the roots of h(t) = (139kt)^2 − 69t + 80

Sonbull [250]

Answer:

The positive value of $k$ will result in exactly one real root is approximately 0.028.

Step-by-step explanation:

Let $h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80$ , roots are those values of $t$ so that $h(t) = 0$ . That is:

$19321\cdot k^{2}\cdot t^{2}-69\cdot t + 80=0$ (1)

Roots are determined analytically by the Quadratic Formula:

$t = \frac{69\pm \sqrt{4761-6182720\cdot k^{2} }}{38642}$

$t = \frac{69}{38642} \pm \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$

The smaller root is $t = \frac{69}{38642} - \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$ , and the larger root is $t = \frac{69}{38642} + \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$ .

$h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80$ has one real root when $\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} = 0$ . Then, we solve the discriminant for $k$ :

$\frac{80\cdot k^{2}}{19321} = \frac{4761}{1493204164}$

$k \approx \pm 0.028$

The positive value of $k$ will result in exactly one real root is approximately 0.028.

7 0

2 years ago