The expression of integral as a limit of Riemann sums of given integral is 4 ∑ from i=1 to i=n.
Given an integral .
We are required to express the integral as a limit of Riemann sums.
An integral basically assigns numbers to functions in a way that describes displacement, area, volume, and other concepts that arise by combining infinite data.
A Riemann sum is basically a certain kind of approximation of an integral by a finite sum.
Using Riemann sums, we have :
=∑f(a+iΔx)Δx ,here Δx=(b-a)/n
=f(x)=
⇒Δx=(5-1)/n=4/n
f(a+iΔx)=f(1+4i/n)
f(1+4i/n)=
∑f(a+iΔx)Δx=
∑
=4∑
Hence the expression of integral as a limit of Riemann sums of given integral is 4 ∑ from i=1 to i=n.
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Answer:
AB = 5/4 y - 1 = 5/4 (12/13) -1 = 2/13
AC= 7/3 y - 2 = 7/3 (12/13) -2 = 2/13
Step-by-step explanation:
Because it is a equilateral triangle, it means all sides have the same length.
AB = AC
5/4 y - 1 = 7/3 y - 2
5/4 y - 7/3 y = -2 +1
-13/12 y = -1
y = 12/13
input y to the equation.
AB = 5/4 y - 1 = 5/4 (12/13) -1 = 2/13
AC= 7/3 y - 2 = 7/3 (12/13) -2 = 2/13
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Answer:
cant help you there buddy
Step-by-step explanation: sorry
Do the top equation and that fraction line means devide so u devide the answers u get for the top and bottom
it might be 5 if you subtract 13 from 8