Answer: 1.) 10
Step-by-step explanation:
-4 + 4 = 0
0 + 6 = 6
6 + 4 = 10
now, we're making the assumption that the front and back of the tent are trapezoidal, Check the picture below.
![\textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} h=height\\ a,b=\stackrel{parallel~sides}{bases}\\[-0.5em] \hrulefill\\ h=32\\ a=23\\ b=36.5 \end{cases}\implies \begin{array}{llll} A=\cfrac{32(23+36.5)}{2}\implies A=952 \\\\\\ \stackrel{\textit{twice that much}}{2A=1904} \end{array}](https://tex.z-dn.net/?f=%5Ctextit%7Barea%20of%20a%20trapezoid%7D%5C%5C%5C%5C%20A%3D%5Ccfrac%7Bh%28a%2Bb%29%7D%7B2%7D~~%20%5Cbegin%7Bcases%7D%20h%3Dheight%5C%5C%20a%2Cb%3D%5Cstackrel%7Bparallel~sides%7D%7Bbases%7D%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20h%3D32%5C%5C%20a%3D23%5C%5C%20b%3D36.5%20%5Cend%7Bcases%7D%5Cimplies%20%5Cbegin%7Barray%7D%7Bllll%7D%20A%3D%5Ccfrac%7B32%2823%2B36.5%29%7D%7B2%7D%5Cimplies%20A%3D952%20%5C%5C%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Btwice%20that%20much%7D%7D%7B2A%3D1904%7D%20%5Cend%7Barray%7D)
The correct answer for this question is letter C, because then you know that PS = SR, QS = QS (of course) and PQ=QR (given), then triangles are congruent and thus angle QPS equals angle QRS and the triangle PQR is then isosceles
-8 < x > 8
This is how it would look
Answer:
4, 7, 6, 9
Step-by-step explanation:
Its easy. X and Y stuff