Answer:
<u>First question answer:</u> The limit is 69
<u>Second question answer:</u> The limit is 5
Step-by-step explanation:
For the first limit, plug in
in the expression
, that's the answer for linear equations and limits.
So we have:
![9x-3\\9(8)-3\\72-3\\69](https://tex.z-dn.net/?f=9x-3%5C%5C9%288%29-3%5C%5C72-3%5C%5C69)
The answer is 69
For the second limit, if we do same thing as the first, we will get division by 0. Also indeterminate form, 0 divided by 0. Thus we would think that the limit does not exist. But if we do some algebra, we can easily simplify it and thus plug in the value
into the simplified expression to get the correct answer. Shown below:
![\frac{x^2+8x-9}{x^2-1}\\\frac{(x+9)(x-1)}{(x-1)(x+1)}\\\frac{x+9}{x+1}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%5E2%2B8x-9%7D%7Bx%5E2-1%7D%5C%5C%5Cfrac%7B%28x%2B9%29%28x-1%29%7D%7B%28x-1%29%28x%2B1%29%7D%5C%5C%5Cfrac%7Bx%2B9%7D%7Bx%2B1%7D)
<em>Now putting 1 in
gives us the limit:</em>
![\frac{x+9}{x+1}\\\frac{1+9}{1+1}=\frac{10}{2}=5](https://tex.z-dn.net/?f=%5Cfrac%7Bx%2B9%7D%7Bx%2B1%7D%5C%5C%5Cfrac%7B1%2B9%7D%7B1%2B1%7D%3D%5Cfrac%7B10%7D%7B2%7D%3D5)
So the answer is 5
Answer:
![5a^2+\frac{2a}{3} + 9](https://tex.z-dn.net/?f=5a%5E2%2B%5Cfrac%7B2a%7D%7B3%7D%20%2B%209)
Step-by-step explanation:
Refer to file. Trying something different. Should be easier to read than text format and is easier than mathML.
The answer is -4 2/3
Explanation : The elevator is at 0, and went below ground level 90 feet, that would be -90, then it went up 20 feet, which would be -90 + 20 = -70
-70 ft / 15sec = - 4 2/3
I am not sure about the ground level and negative difference but that it is what I was taught. Below ground level is negative and above is positive. Therefore the elevator traveled up and it traveled -4 2/3 per second.
It so either 4 2/3 or - 4 2/3 but pretty sure it is - 4 2/3.
:)))