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3 years ago

Heeeelp pls i beg of you

Mathematics

1 answer:

Marat540 [252]3 years ago

5 0

Answer: 41.6%

Step-by-step explanation:

You divide the amount of trees 40ft or taller (10) by the total number of trees (24) so 10/24 = .416 (41.6%)

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PLS HELP I WILL GIVE BRAINLEST

Lady_Fox [76]

Answer:

50 is the best choice

Step-by-step explanation:

it is better if its an even number and higher

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2 years ago

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RSB [31]

D. is the answer.

your welcome hunty

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3 years ago

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How do I do this?<br>*Look at the directions in the photo*

lora16 [44]

Answer:

$Area\ of\ material\ required\ for\ the\ first\ box=384\ inches^2\\Area\ of\ material\ required\ for\ the\ second\ box=486\ inches^2\\Area\ of\ material\ required\ for\ the\ first\ box=600\ inches^2\\Total\ Area\ of\ material\ required=1470\ inches^2$

Step-by-step explanation:

$We\ are\ given:\\Diameter\ of\ the\ first\ volleyball=8\ inches \\Diameter\ of\ the\ second\ volleyball=9\ inches\\Diameter\ of\ the\ third\ volleyball= 10\ inches.\\Hence,\\We\ know\ that,\\If\ the\ side\ of\ the\ cube\ box\ is\ s, it's\ Total\ Surface\ Area\ =No.\ of\\ faces\ in\ a\ regular\ polyhedron\ *Area\ of\ each\ face\ of\ the\ polyhedron=6*s^2=6s^2\\Hence,\\Lets\ apply\ this\ equation\ in\ finding\ the\ area\ of\ material\ required\ for\ the\\ three\ cases.\\$

$As\ the\ volleyball\ should\ wholly\ fit\ into\ the\ box,\ the\ diameter\ of\ the\\ volleyballs\ would\ be\ the\ side\ of\ the\ cube\ box.\\Hence,\\For\ the\ first\ volleyball,\\Diameter\ of\ the\ first\ volleyball=8\ inches\\Hence,\\Side\ of\ the\ cubical\ box\ for\ the\ first\ volleyball=8\ inches.\\Hence,\\The\ Total\ Surface\ Area\ of\ the\ first\ box=6s^2=6*8*8=384\ inches^2$

$For\ the\ second\ volleyball,\\Diameter\ of\ the\ second\ volleyball=9\ inches\\Hence,\\Side\ of\ the\ cubical\ box\ for\ the\ second\ volleyball=9\ inches.\\Hence,\\The\ Total\ Surface\ Area\ of\ the\ second\ box=6s^2=6*9*9=486\ inches^2$

$For\ the\ third\ volleyball,\\Diameter\ of\ the\ third\ volleyball=8\ inches\\Hence,\\Side\ of\ the\ cubical\ box\ for\ the\ third\ volleyball=10\ inches.\\Hence,\\The\ Total\ Surface\ Area\ of\ the\ third\ box=6s^2=6*10*10=600\ inches^2$

$Hence,\\If\ you\ are\ asked\ the\ Total\ Area\ to\ make\ all\ the\ boxes,\\ you\ just\ add\ them\ together.\\Hence,\\Total\ Area\ of\ Material\ required\ to\ make\ the\ three\ boxes=384+486+600=1470\ inches^2$

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2 years ago

Is 3.14596387 a rational number?

zaharov [31]

No it is an irrational number

8 0

3 years ago

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3/4 + 3/4 + 3/4 = 9 x ?

Dominik [7]

$\frac{3}{4} + \frac{3}{4} + \frac{3}{4} = 9x \\ \\ \frac{9}{4} = 9x \\ \\ \frac{9}{4 \times 9} = x \\ \\ \frac{9}{36} = x \\ \\ x = \frac{1}{4} \\ \\$

The answer is: x = 1/4 or x = 0.25.

7 0

3 years ago

Heeeelp pls i beg of you​

Heeeelp pls i beg of you