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lozanna [386]
2 years ago
15

Select the inequality that corresponds to the figure

Mathematics
1 answer:
Gnoma [55]2 years ago
3 0

Answer:

Although the Line is included in the region, I will say the your answer is B and D

Step-by-step explanation:

The region shaded is below the Line graph, son we have a < sign, now, I can see the region including the Line graph, so I will say that the inequality should have the = sign, nevertheless no options include the =sign, so, if it is nothing missing, your answer should be:

y<x

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Leila says that 75% of a number will always be greater than 50% of any other number. Complete one inequality to support Leilas c
Greeley [361]
If a number is positive, Leila's theory that 75% of a number will always be greater than 50% of another number is <em>true</em>;<em> </em>however, if both numbers are negative, or if the number of which she finds 50% is much greater than the number of which she finds 75%, Leila's theory could be incorrect.

This inequality shows that Leila is correct: 100(0.75) \geq 50(0.50) (which simplifies to 75 \geq 25)

This inequality shows that Leila is incorrect: 50(0.75) \geq 100(0.50) (which simplifies to 37.5 \geq 50)

Hope this helps!
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DaniilM [7]

Answer:

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Step-by-step explanation:

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3 years ago
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Determine the function
zalisa [80]

For each increment in x, the output is multiplied by 2. The function could be written the way a geometric sequence can be written:

... f(x) = 5·2^(x-1)

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3 years ago
8. How many ways can a committee of 5 students be chosen from a student council of 30 students? Is the order in which the member
tankabanditka [31]

Answer: A committee of 5 students can be chosen from a student council of 30 students in 142506 ways.

No , the order in which the members of the committee are chosen is not  important.

Step-by-step explanation:

Given : The total number of students in the council = 30

The number of students needed to be chosen = 5

The order in which the members of the committee are chosen does not matter.

So we Combinations (If order matters then we use permutations.)

The number of combinations of to select r things of n things = ^nC_r=\dfrac{n!}{r!(n-r)!}

So the number of ways a committee of 5 students can be chosen from a student council of 30 students=^{30}C_5=\dfrac{30!}{5!(30-5)!}

=\dfrac{30\times29\times28\times27\times26\times25!}{(120)\times25!}=142506

Therefore , a committee of 5 students can be chosen from a student council of 30 students in 142506 ways.

4 0
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