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ss7ja [257]
3 years ago
15

Which of the following expressions is equal to 3 to the fifth power times 3 to the second power

Mathematics
1 answer:
Anit [1.1K]3 years ago
7 0

Answer:

If I did this problem right, it should be 2,187

Step-by-step explanation:

3 to the fifth power is 243

3 to the second power is 9

253 x 9 =2187

Hope this helps!

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Answer:

1 1/8

Step-by-step explanation:

divide 9 and 8 and u get ur answer Hoped I helped im Eve btw. Have a great day and consider marking this brainliest if you do thank you in advanced!

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i have a $500 in my account after 4 years of investing at 2.5% per year, how much money did I start with?
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3 years ago
An automobile manufacturer would like to know what proportion of its customers are not satisfied by the service provided by the
zheka24 [161]

Answer:

The sample size needed if the margin of error of the confidence interval is to be about 0.04 is 18.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

Past studies suggest this proportion will be about 0.15

This means that p = 0.15

Find the sample size needed if the margin of error of the confidence interval is to be about 0.04

This is n when M = 0.04. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.04 = 1.96\sqrt{\frac{0.15*0.85}{n}}

0.04\sqrt{n} = 1.96\sqrt{0.15*0.85}

\sqrt{n} = \frac{1.96\sqrt{0.15*0.85}}{0.04}

(\sqrt{n})^{2} = (\frac{1.96\sqrt{0.15*0.85}}{0.04})^{2}

n = 17.5

Rounding up

The sample size needed if the margin of error of the confidence interval is to be about 0.04 is 18.

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3 years ago
John is 4 inches taller than David, who is K inches tall. Write an expression for johns hight in inches
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3 years ago
7, 10, 13, 16, find the 43rd term<br> A)75<br> B)133<br> C)121<br> D)101
uranmaximum [27]
I think it’s 121 i could be wrong tho://
7 0
3 years ago
Read 2 more answers
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