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netineya [11]
3 years ago
8

Manny is paid semimonthly. His semimonthly salary is $1,239. What is his annual salary?

Mathematics
1 answer:
Alja [10]3 years ago
5 0

Answer:

Semimonthly is twice a month. There are 12 months in a year, which means Manny will get paid 12 x 2 = 24 times a year.

His annual salary is:

$1,239 x 24 = $29,736

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Calculate the average rate of change for the given graph from x = 0 to x = 3 and select the correct answer below. (0,6) (3,0) ​
algol13

Answer:

(3,0)

Step-by-step explanation:

The number on the x axis is the only number that changes not the number on the y axis.  

5 0
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4. Find the monthly average for each list of year-end utility costs given:
BigorU [14]

Answer:

1486.67 or 1487.

Step-by-step explanation:

Find the average of those three things. Add 2,340 plus 470 plus 1650. You get 4460. Since you have three costs, divided 4460 by 3, which is 1486.6 repeating. Round to the nearest hundredth which is 1486.67. Hope this helps!

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4 years ago
What is the common factors of 30 25 and 40
sattari [20]
5 and 1 are the common factor between them 
7 0
3 years ago
How do I correctly solve this?
Gelneren [198K]
<h3>Answer: y = 14</h3>

===================================

Explanation:

The two angles involving x add up to 180 degrees. This is because they are same side interior angles (and because the horizontal lines are parallel)

So,

(angle BCF) + (angle EFC) = 180

(5x - 66) + (2x + 50) = 180

5x - 66 + 2x + 50 = 180

7x - 16 = 180

7x - 16+16 = 180+16 ... add 16 to both sides

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7x/7 = 196/7 .... divide both sides by 7

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This will be used to help find y

Notice how the angles BCF and ACD are vertical angles, therefore they are congruent or the same measure

angle ACD = angle BCF

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9y = 126

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3 0
4 years ago
Read 2 more answers
The number of typing errors made by a typist has a Poisson distribution with an average of seven errors per page. If more than s
Aleks [24]

Answer:

0.599  is the probability that a randomly selected page does not need to be retyped.

Step-by-step explanation:

We are given the following in the question:

The number of typing errors made by a typist has a Poisson distribution.

\lambda  =7

The probability is given by:

P(X =k) = \displaystyle\frac{\lambda^k e^{-\lambda}}{k!}\\\\ \lambda \text{ is the mean of the distribution}

We have to find the probability that a  randomly selected page does not need to be retyped

P(less than or equal to 7 mistakes in a page)

P( x \leq 7) = P(x =1) + P(x=1) +...+ P(x=6) + P(x = 7)\\\\= \displaystyle\frac{7^0 e^{-7}}{0!} + \displaystyle\frac{7^1 e^{-7}}{1!} +...+ \displaystyle\frac{7^6 e^{-7}}{6!} + \displaystyle\frac{7^7 e^{-7}}{7!} \\\\= 0.59871\approx 0.599

Thus, 0.599  is the probability that a randomly selected page does not need to be retyped.

4 0
3 years ago
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