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3 years ago

determine the constant of variation for the direct variation R varies directly with S is given 16, R is 80

Mathematics

1 answer:

valina [46]3 years ago

8 0

Answer:

Step-by-step explanation:

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Penny is counting the days until her grandma comes to visit. There are 98 days left. How many weeks are left until Penny's grand

Lorico [155]

Create a unit rate.
1 wk/ 7 days
x wk/ 98 days
Cross multiply.
98=7x
Solve the equation.
14=x
14 weeks until her grandmother visits

3 0

3 years ago

Find the value of x and y

sineoko [7]

Step-by-step explanation:

5x-17 and 3x-11 are supplementary angles

They add up to 180 degrees

5x-17 + 3x - 11 = 180

8x - 28 = 180

8x= 208

x= 26

3x-11, 90, and 2y + 5 added together equal 180

3x-11 + 90 + 2y + 5 = 180

3(26) - 11 + 2y + 5 = 90

78 - 6 + 2y = 90

72 + 2y = 90

2y = 18

y = 9

I hope this helps!!!

5 0

3 years ago

Convert the rectangular coordinates (-9, 3V3) into polar form. Express the angle

Whitepunk [10]

Answer:

$(6\sqrt{3},\,\frac{5\pi}{6})$

Step-by-step explanation:

The radius r can be found from the relationship

$r^2=x^2+y^2\\r^2=(-9)^2+(3\sqrt{3})^2\\r^2=81+27=108\\r=\sqrt{108}\\r=6\sqrt{3}$

The point is in Quadrant II (-, +), so use the inverse cosine function to find the angle.

$\cos{\theta}=\frac{x}{r}=\frac{-9}{6\sqrt{3}}\\\cos{\theta}=-\frac{9}{6\sqrt{3}} \cdot \frac{\sqrt{3}}{\sqrt{3}}\\\cos{\theta}=-\frac{9\sqrt{3}}{6\cdot3}\\\cos{\theta}=-\frac{\sqrt{3}}{2}\\\\\cos^{-1}\frac{-\sqrt{3}}{2}}=\frac{5\pi}{6}$

See the attached image.

7 0

3 years ago

-3x^2+6x+1=4 find the discriminant of each quadratic equation then state the number and type solutions

ipn [44]

Answer:

S={( 1 )}

Step-by-step explanation:

-3x²+6x+1=4

-3x²+6x+1-4=0

-3x²+6x-3=0

∆=b²-4.a.c

∆=(6)²-4.(-3).(-3)

∆=36-36

∆=0

x'=x"=-b/2a=-(+6)/2.(-3)=-6/-6=1

3 0

3 years ago

Read 2 more answers

A bakery the price of the cake is nine dollars more than the price of a pie. One day the bakery sold 8 cakes and 14 pies for a t

gavmur [86]

Answer:

The price of the cake is $24 and the price of the Pie is $15

Step-by-step explanation:

Given

<em>Represent price of Cake with C and Price of Pie with P</em>

$C = 9 + P$

Cakes sold = 8

Pies sold = 14

$Total = \$402$

Required

Determine C and P

To represent the cakes and pies sold, we have the following expression

$8C + 14P = 402$

Substitute 9 + P for C

$8(9+P) + 14P = 402$

Open the bracket

$72 + 8P + 14P = 402$

Collect Like Terms

$8P + 14P = 402 - 72$

$22P= 330$

Divide both sides by 22

$P = \frac{330}{22}$

$P = 15$

Recall that

$C = 9 + P$

$C = 9 + 15$

$C = 24$

<em>Hence, the price of the cake is $24 and the price of the Pie is $15</em>

7 0

3 years ago