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3 years ago

What is the area of this composite figure?

Mathematics

1 answer:

Mkey [24]3 years ago

6 0

We have two congruent trapezoids.

The formula of an area of a trapezoid:

$A=\dfrac{base_1+base_2}{2}\cdot\ height$

We have:

$base_1=210\ mm\\\\base_2=150\ mm\\\\height=55\ mm$

Substitute:

$A=\dfrac{210+150}{2}\cdot55=\dfrac{360}{2}\cdot55=180\cdot55=9,900\ mm^2$

Answer:

$2A=2\cdot9,900\ mm^2=19,800\ mm^2$

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What number do you reach when you start at -7 and move 3 units to the right

Vesna [10]

Answer: The number you reach would be -4

Step-by-step explanation:

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3 years ago

The maximum amount you can spend for renting a motor scooter is $50. The rental fee is $12 and the cost per hour is $9.50. Solve

uranmaximum [27]

The maximum number of hours for which you can rent the scooter is: 4 hours

<h3>Cost of renting;</h3>

According to the question;

The maximum amount you can spend for renting a motor scooter is $50
The rental fee is $12 and the cost per hour is $9.50.

The inequality to determine the maximum number of hours you can rent the scooter is;

$12 + $9.50h <= $50

Solving the inequality, we have;

$9.50h <= $38

h <= 4hours.

Read more on cost of renting;

brainly.com/question/10563785

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2 years ago

Which word best describes the degree of overlap between the two data sets?

snow_tiger [21]

Answer:

Moderate

Step-by-step explanation:

I think sorry if its wrong

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2 years ago

There are 450 students in the 9th and 10th grade taking geometry, and 1/3 of them are 9th graders

algol13

There are 150 9th graders and 300 10th graders

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3 years ago

Read 2 more answers

1. A farmer divided a field into 1-foot by 1-foot sections and tested soil samples from 32 randomly selected sections in the fie

Ad libitum [116K]

Part A

Answers:
Mean = 5.7
Standard Deviation = 0.046

-----------------------

The mean is given to us, which was 5.7, so there's no need to do any work there.

To get the standard deviation of the sample distribution, we divide the given standard deviation s = 0.26 by the square root of the sample size n = 32
So, we get s/sqrt(n) = 0.26/sqrt(32) = 0.0459619 which rounds to 0.046

================================================

Part B

The 95% confidence interval is roughly (3.73, 7.67)
The margin of error expression is z*s/sqrt(n)
The interpretation is that if we generated 100 confidence intervals, then roughly 95% of them will have the mean between 3.73 and 7.67

-----------------------

At 95% confidence, the critical value is z = 1.96 approximately

ME = margin of error
ME = z*s/sqrt(n)
ME = 1.96*5.7/sqrt(32)
ME = 1.974949
The margin of error is roughly 1.974949

The lower and upper boundaries (L and U respectively) are:
L = xbar-ME
L = 5.7-1.974949
L = 3.725051
L = 3.73
and
U = xbar+ME
U = 5.7+1.974949
U = 7.674949
U = 7.67

================================================

Part C

Confidence interval is (5.99, 6.21)
Margin of Error expression is z*s/sqrt(n)
If we generate 100 intervals, then roughly 95 of them will have the mean between 5.99 and 6.21. We are 95% confident that the mean is between those values.

-----------------------

At 95% confidence, the critical value is z = 1.96 approximately

ME = margin of error
ME = z*s/sqrt(n)
ME = 1.96*0.34/sqrt(34)
ME = 0.114286657
The margin of error is roughly 0.114286657

L = lower limit
L = xbar-ME
L = 6.1-0.114286657
L = 5.985713343
L = 5.99

U = upper limit
U = xbar+ME
U = 6.1+0.114286657
U = 6.214286657
U = 6.21

5 0

3 years ago